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3 years ago

Hi please help me ill give you uh brainlest

Mathematics

2 answers:

victus00 [196]3 years ago

7 0

Answer:

1.1

Step-by-step explanation:

Checked my work on a calculator and it's corect!! I hope this helps!!!

alina1380 [7]3 years ago

6 0

Answer:

is answer

plz mark as brainliest plz

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What is the following sum?<br>(please show how you worked it out)

AleksAgata [21]

Answer:

$4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )$

Step-by-step explanation:

Let's start by breaking down each of the radicals:

$\sqrt[3]{16x^3y}$

Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of $x^3$ , and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:

$\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}$

We can apply this same technique of "extracting cubes" to the second term:

$\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}$

Replacing those two expressions in the parentheses leaves us with this monster:

$2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})$

What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:

$4, \sqrt[3]{2} , x$

We can factor those out to give us a final, simplified expression:

$4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )$

Not that this is the same sum as we had at the beginning; we've just extracted all of the cube roots that we could in order to rewrite it in a slightly cleaner form.

6 0

3 years ago

Which is greater 2/3 5/10 7/8 1/2 ?

jasenka [17]

Answer:7/8!!!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the direction of a line with the slope 3/-2

adelina 88 [10]

3\div-2= \frac{-3}{2}3÷−2=2−3 direction of a line with the slope

3 0

3 years ago

Rewrite 256 in exponential form using 2 as the base

AlexFokin [52]

256=2^8
256 is 2^8
I hate this " at least 20 characters to explain" may be the answer doesn't need to be explained so much

5 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago