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3 years ago

Is 5/21 rational or irrational number ?

Mathematics

1 answer:

ZanzabumX [31]3 years ago

6 0

Answer:

rational

Step-by-step explanation:

irrational numbers can not be expressed as a fraction

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Jose earns $3680 per month, of which 22% is taken out for federal and state income taxes and other required deductions. Last mon

zzz [600]

Answer: 30%

Step-by-step explanation:

Firstly, we find 22% of $3680. This will be:

= 22% × $3680

= 0.22 × $3680

= $809.60

Therefore, his take home pay will be:

= $3680 - $809.60

= $2870.40

We are further told that last month he spent $775 for rent and 86.12 on clothing. The amount combined will be:

= $775 + $86.12

= $861.12

The percent of his take-home pay did he spend on rent and clothing combined will be:

= 861.12 / 2870. 40 × 100

= 30%

3 0

3 years ago

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Help help help help help help help hepl

matrenka [14]

Answer:

the answer is uh..21

Step-by-step explanation:

Cancel the common Factors of 3^2 and 3

Which will equal 7x(3)

Multiply 7x(3)

That would be 21 :)

~brett <3

8 0

3 years ago

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What is the equation of the line shown in the graph drag & drop the expressions ro write the equation of the line in slope i

vredina [299]

Answer:

y = 2(x + 3) + (-2) is the required equation.

Step-by-step explanation:

Here the given points are A( -1,2) and B(-3-2)

Now, slope of the equation = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 -2}{-3-(-1)} = \frac{-4}{-2} = 2$

Hence, the slope of the equation is m = 2

Now, by POINT SLOPE FORMULA:

The equation of a line with slope m and point (x0, y0) is given as

(y - y0) = m (x -x0)

So, here the equation of line with (-3, -2) is

y - (-2) = 2 (x - (-3))

or, y + 2 = 2(x + 3)

⇒ y = 2(x + 3) + (-2) is the required equation.

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4 years ago

Students at a middle school were surveyed on how they get to school. Out of 230 students, 10% said they ride their bikes to scho

Shalnov [3]

Answer:

10% is equivalent to the unit fraction 1/10.

To find 10% of 230, divide 230 by 10.

10% of 230 is 23.

7 0

3 years ago

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How do you do this problem? Simple and concise explanation, please!

natita [175]

Step-by-step Answer:

This is a problem of partial fractions.

Step 1:

factor all denominators on the left-hand side (LHS).

LHS = a/[(x+1)(x-1)] + x/[(x-3)(x+1)]

Note the common factor (x+1) in both denominators, which makes the combined/common denominator [(x+1)(x-1)(x-3)]

Step 2:

multiply each term, top and bottom, by the factor "missing" from the common denominator.

The first term is missing (x-3), the second term is missing (x-1)

a(x-3)/[(x+1)(x-1)(x-3)] + x(x-1)/[(x+1)(x-1)(x-3)]

which can be simplified to:

[a(x-3)+x(x-1)]/[(x+1)(x-1)(x-3)]

Expand numerator:

[x^2 + ax-x -3a]/[(x+1)(x-1)(x-3)]

Step 3:

For the two expressions on each side of the equal sign (LHS and RHS) to be equivalent (for ALL values of x), the numerators and denominators must be identical when expanded, so

For denominator, we have factors [(x+1)(x-1)(x-3)], or b,c,d = -3, -1, 1 (in ascending order).

For the numerator, we need to have LHS = RHS

x^2 + (a-1)x -3a = x^2 + 2x -9

putting a=3 gives the

LHS = x^2 + (3-1)x -3(3) = x^2 + 2x - 9 which makes equality with the RHS.

So we have solved for all values required.

6 0

3 years ago