Question

What is the y-value in the solution to this system of linear equations?

Answer 1

Answer:

Option A is correct that is y = -4

Step-by-step explanation:

Given System of Equations are ,

4x + 5y = -12 ...............(1)

-2x + 3y = -16 .................(2)

To find: value of y in the solution.

We solve it by substitution method,

from equation (1)

$4x =-12-5y$

$x=\frac{-12-5y}{4}$

Put this value of x in equation (2)

$-2(\frac{-12-5y}{4})+3y=-16$

$\frac{12+5y}{2}+3y=-16$

$\frac{12+5y+6y}{2}=-16$

$12+11y=-32$

$11y=-32-12$

$11y=-44$

$y=-4$

Therefore, Option A is correct that is y = -4.

Answer 2

4x+5y=-12 (1)
-4x+6y=-32 (2)
(1)+(2)=> 11y=-44
y=-4
so A : -4