Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
Step-by-step explanation:
Answer:
Area of triangle = 20√2
Step-by-step explanation:
Formula:
Area of triangle = bh/2
b - base of triangle
h - height of triangle
<u>Distance formula</u>
d = √(x₂ - x₁)² +(y₂ - y₁)²
From the figure we can see that, the given triangle is right angled triangle.
Base = AC and Height = AB
<u>To find AB and AC</u>
A(1,3), B(4,7) and C(9, -5)
AB = √(4 - 1)² +(7 - 3)² = √(3² + 4²) = 5
AC = √(9 - 1)² +(-5 - 3)² = √(8² + -8²) = 8√2
<u>To find the are of triangle</u>
Area = bh/2 = (5* 8√2)/2 = 20√2
Therefore the area of triangle = 20√2 square units
X= 1.80/10 . x is the number of dimes. 1.80 is your total and 10 represents the worth of the dime
Answer:D’ (0, -1)
Step-by-step explanation:
