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3 years ago

What is the speed of an airplane that travels 4500 miles in 6 hours?

Physics

2 answers:

MakcuM [25]3 years ago

6 0

Answer:

750 miles / hour

Explanation:

velocity = distance / time

= 4500 miles / 6 hours

= 750 miles / hour

aniked [119]3 years ago

5 0

Given:-

Speed of the airplane (s) = 4500 miles
Time taken (t) = 6 h

To Find: Speed (v) of the particle (airplane).

We know,

s = vt

where,

s = Distance,
v = Speed &
t = Time taken.

Similarly,

v = s/t

→ v = (4500 miles)/(6 hours)

→ v = 750 miles/hour ...(Ans.)

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If the conductor isn't working it would be blocked

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State Newton’s Second Law of Motion. Provide an expression for it and explain each term in

Viefleur [7K]

Answer:

F=ma

Explanation:

Force equals mass times acceleration. Aka, the mass of an object times change in speed equals force applied on it.

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3 years ago

You see the boy next door trying to push a crate down the sidewalk. He can barely keep it moving, and his feet occasionally slip

Murrr4er [49]

Answer:

Explanation:

Given that the weight of the crate is

M=48kg

Then, weight of boy is

W=mg=48×9.8=470.4N

ΣF = ma ,Along y axis

Since the body is not moving in y direction then, a=0 along y axis

N-W=0

N=W

The normal equals weight of boy

N=470.4N

Then, applying frictional force opposing the boy motion.

Fr=μN

Fr=0.5×470.4

Fr=235.2N

Then, this is the forward force that the boy try using to pull the crate.

Since he can barely move his foot he has not yet overcome the coefficient of static friction.

ΣF = ma. , along x-axis

a along x-axis is 0 since he cannot move his foot, I.e he was not moving

F-Fr= 0

F=Fr=235.2N

The forward force the boy apply is 235.2N on the crate

Also, analysing the crate.

The forward force is now F=235.2N

Then the frictional force =Fr

Then,

ΣF = ma. , along x-axis

a along x-axis is 0 since the crate did not move,

F-Fr=0

Fr=F=235.2N

This is the frictional force on the crate.

Then using frictional law

Fr=μN

N=Fr/μ

N=235.2/0.9

N=261.33N

Now this normal is equal to the weight of the crate

ΣF = ma ,Along y axis

Since the body is not moving in y direction then, a=0 along y axis

N-W=0

W=N=261.33N

Then, since weight is given as

W=mg

m=W/g

m=261.33/9.81

m=26.64kg

The mass of the crate is 26.64kg

7 0

3 years ago

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An elevator (mass 4100 kg) is to be designed so that the maximum acceleration is 0.0400g. what is the maximum force the motor sh

melomori [17]

Answer:

The maximum force on the supporting cable is 80688 N.

The minimum force on the supporting cable is -164 N.

Explanation:

For maximum force movement of elevator is in upward direction. Thus, equation of motion is given by,

ma = T - mg

where m is the mass of elevator

a is acceleration of elevator

g is acceleration due to gravity

T is the maximum tension in the supporting cable

T = ma + mg

T = m (a + g)

T = 4100 ( 0.04g + 9.8)

T = 80688 N

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ma = T - mg

where m is the mass of elevator

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g is acceleration due to gravity

T is the minimum tension in the supporting cable

T = ma + mg

T = m (a + g)

T = 4100 ( 9.8 - 0.04g)

T = -164 N

This is the minimum force on the supporting cable.

7 0

3 years ago