Answer: thickness h = 0.014cm
Question: In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.30 inches in diameter and have a mass of 1.50 g of silicon. How thick (mm) is each wafer if silicon has a density of 2.33 g/cm 3 ? (The volume of a cylinder is V=πr 2 h )
Explanation:
The volume of a cylinder is
Volume V = πr^2h ....1
The density of a material is
Density D = mass m / volume V
D = m/V ....2
Since m and D are given, we can make V the subject of formula.
V = m/D ....3
From equation 1, we need to derive the thickness h of the cylindrical silicon.
h = V/πr^2 .....4
Substituting equation 3 into 4
h = (m/D)/πr^2 .....5
Given.
mass m = 1.50g
density D = 2.33g/cm^3
radius r = diameter/2 = 3.00in/2 = 7.62/2 cm = 3.81cm
Substituting the given values into the equation
h = (1.5/2.33)/(π ×3.81^2)
thickness h = 0.014cm
Answer:
Explanation:
I think the answer is statement no 3.
Hope it helps.
Answer:
The correct answer to the following question will be Option A (I1 > I2).
Explanation:
Method for moment of inertia because of it's viewpoint including object at a mean distance "r" from the axis is,
⇒ mr²
<u>For Case 1:</u>
Let the length of a rod be "r".
The axis passes via the middle of that same rod so that the range from either the axis within each dumbbell becomes "
".
Now,
Now total moment of inertia = sum of inertial moment due to all of the dumbbell
⇒ 
⇒ 
<u>For Case 2:</u>
Axis moves via one dumbbell because its range from either the axis becomes zero (0) and its impact is zero only at inertia as well as other dumbbell seems to be at a range "r" from either the axis
Now,
Total moment of inertia = moment of inertia of dumbbell at distance "r".

And now we can infer from this one,
⇒ 
So that "I1 > I2" is the right answer.
Answer:
mercury vapour
Explanation:
it contains many other gases and it contains mercury vapour
D 193 is the right answer if not try c because it is in between them both