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DENIUS [597]
4 years ago
6

Two spherical objects have a combined mass of 190 kg . The gravitational attraction between them is 8.27×10−6 N when their cente

rs are 19.0 cm apart.1.) What is the mass of the heavier object? (kg)
2.) What is the mass of the lighter object? (kg)
Physics
1 answer:
pogonyaev4 years ago
3 0

Explanation:

It is given that,

Let m_1\ and\ m_2 are the masses of two objects such that,

m_1+m_2=190\ kg............(1)

Force between them, F=8.27\times 10^{-6}\ N

Distance between masses, d = 19 cm = 0.19 m

The gravitational force between two masses is given by :

F=G\dfrac{m_1m_2}{d^2}  

m_1m_2=\dfrac{Fd^2}{G}

m_1m_2=\dfrac{8.27\times 10^{-6}\times (0.19)^2}{6.67\times 10^{-11}}

m_1m_2=4475.96.............(2)

On solving equation (1) and (2),

Mass of heavier object, m_1=162.44\ kg

Mass of lighter object, m_2=27.55\ kg

Hence, this is the required solution.

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Explanation:

The volume of a cylinder is

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D = m/V ....2

Since m and D are given, we can make V the subject of formula.

V = m/D ....3

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Substituting equation 3 into 4

h = (m/D)/πr^2 .....5

Given.

mass m = 1.50g

density D = 2.33g/cm^3

radius r = diameter/2 = 3.00in/2 = 7.62/2 cm = 3.81cm

Substituting the given values into the equation

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3 years ago
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Explanation:

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Answer:

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Explanation:

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<u>For Case 1:</u>

Let the length of a rod be "r".

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Now,

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<u>For Case 2:</u>

Axis moves via one dumbbell because its range from either the axis becomes zero (0) and its impact is zero only at inertia as well as other dumbbell seems to be at a range "r" from either the axis

Now,

Total moment of inertia = moment of inertia of dumbbell at distance "r".

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And now we can infer from this one,

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