Answer:
<em>The probability of obtaining the letter p twice is 1/121</em>
Step-by-step explanation:
<u>Probability of Recurring Events</u>
There are 11 letters in the word 'independent', one of which is the letter 'p'.
When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.
This means the individual probability of getting a 'p' is:
![\displaystyle P_1=\frac{1}{11}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20P_1%3D%5Cfrac%7B1%7D%7B11%7D)
The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:
![\displaystyle P_2=\frac{1}{11}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20P_2%3D%5Cfrac%7B1%7D%7B11%7D)
We'll use the multiplication rule. Just multiply the probability of the first event by the second.
![\displaystyle P=P_1*P_2=\frac{1}{11}*\frac{1}{11}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20P%3DP_1%2AP_2%3D%5Cfrac%7B1%7D%7B11%7D%2A%5Cfrac%7B1%7D%7B11%7D)
![\displaystyle P=\frac{1}{121}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20P%3D%5Cfrac%7B1%7D%7B121%7D)
The probability of obtaining the letter p twice is 1/121
Answer:
The answer for this question is A. (4,-4)
Boom ha do boop bam pow oof big dude oof mousse oof sorry I couldn’t help ya son
Distance (d) is 23.46 meters
Workup in the photo below.
Good luck.
X would equal 0 because u would use the distribution 3x+3=3x+3 and then subtract three from the three on the other side and then subtract 3x from 3x and then 0