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Ipatiy [6.2K]
3 years ago
14

5. Si P(x)=2x+4a , Q(x)=4x-2 y P[Q(4)]=60 , Calcular el valor de a

Mathematics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

a = 8

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given P(x) = 2 x+4 a </em>

<em>           Q(x)=4 x - 2</em>

<em>           P( Q(4)) = 60</em>

<em>          P(4 (4) - 2) = 60</em>

<em>         P( 14 ) = 60</em>

<em>        2 (14) + 4 a = 60</em>

<em>         4 a + 28 = 60</em>

<em>Subtracting '28' on both sides , we get</em>

<em>        4 a +28 - 28 = 60 - 28</em>

<em>        4 a = 32</em>

<em>Dividing '4' on both sides , we get</em>

<em>         a = 8</em>

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Answer:

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Step-by-step explanation:

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using the midpoint formula

consider the x- coordinate

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x + 1. 7 = - 7.5 ( subtract 1.7 from both sides )

x = - 16.7

consider the y-coordinate

\frac{1}{2}(y - 4.6 ) = 0.3 ( multiply both sides by 2 )

y - 4.6 = 0.6 ( add 4.6 to both sides )

y = 5.2

endpoint = (- 16.7, 5.2 )


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A similar problem is given at brainly.com/question/13873630

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