Since this is a right triangle and we have an angle and a side we can solve for any other side by using sohcahtoa. Now lets look at what we know we have the angle 35 degrees and the side adjacent to the angle is 10. we are looking for the side opposite to the angle. so we need a formula that uses opposite and adjacent that is toa, tan(angle)=oppisite/adjacent
now lets plug in tan(35)=x/10
x=10*tan(35)
x=7.002 now round to nearest tenth
x=7.0
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Mr.Jones charges $800 per lesson and requires 3 lessons
That means mr Jones will charge Samantha 800x3 = $2400 in total.
Mr. Police charges $62 per lesson and requires 4 lessons,
62x4 = $248 in total.
Since mr. Police charges less than mr.Jones, it would be a better deal for Samantha.
IN CASE YOU WROTE THE QUESTION WRONG AND MR JONES CHARGES $80 PER LESSON
In that case it would be 80x3 = $240 in total
mr jones would charge less now and it would be better deal for Samantha.
I think 1 because if you had 2 you'll end up with a shape that is greater than 180 degrees. Keep in mind obtuse angles a over 90 degrees. hope that helped
Answer:
w + 2.3 > 18
Step-by-step explanation:
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