Answer:1/4
Step-by-step explanation:
Answer:
just ignore this whole thing
Answer:
the top 2 and the left bottom corner
Step-by-step explanation:
the first one in the first row is a reflection
the second one in the first row is a rotation
the one on the left bottom corner just moved a unit
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.
Number of sample, n = 41
Mean, u = 43.1 hours
Standard deviation, s = 5.91 hours
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
43.1 ± 1.645 × 5.91/√41
= 43.1 ± 1.645 × 0.923
= 43.1 ± 1.52
The lower end of the confidence interval is 43.1 - 1.52 =41.58
The upper end of the confidence interval is 43.1 + 1.52 =44.62
Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62
Answer:
4. 16.5 minutes 2508 words - Robert
5. 60 words (c)
6.I don't really know sorry :)
Step-by-step explanation:
4. 304 ÷ 2 = 1 minute 152 words - Robert
2508 ÷ 152 = 16.5 minutes 2508 words - Robert
5. 152 × 20 = 3040 words - Robert
483 ÷ 3 = 1 minute 161 words - Michaela
161 × 20 = 3220 words - Michaela
316 ÷ 2 = 1 minute 158 words - Laura
158 × 20 = 3160 words - Laura
= 3220 - 3160
= 60 words (c)
Please give me brainliest ;)