I assume you mean the product of mixed numbers,
3 1/2 × 3 1/2
If we write this as
(3 + 1/2) × (3 + 1/2) = (3 + 1/2)²
we can use the identity
(a + b)² = a² + 2ab + b²
so that
3 1/2 × 3 1/2 = 3² + (2 × 3 × 1/2) + (1/2)²
3 1/2 × 3 1/2 = 9 + 3 + 1/4
3 1/2 × 3 1/2 = 12 1/4
Alternatively, we can first write 3 1/2 as a mixed number:
3 + 1/2 = 6/2 + 1/2 = (6 + 1)/2 = 7/2
Then
3 1/2 × 3 1/2 = 7/2 × 7/2 = (7 × 7) / (2 × 2) = 49/4
and
49/4 = (48 + 1)/4 = ((4 × 12) + 1)/4 = 12 + 1/4
The values of x are 2 and -1.
Solving the equation created by substitution listed in the question:
-2x+14=x²-3x+12
Add 2x to both sides:
-2x+14+2x=x²-3x+12+2x
14=x²-1x+12
Subtract 14 from both sides:
14-14=x²-1x+12-14
0=x²-1x-2
Factoring this, we want factors of -2 that sum to -1; -2(1) = -2 and -2+1=-1:
0=(x-2)(x+1)
Using the zero product property, we know that either x-2=0 or x+1=0:
x-2=0
x-2+2=0+2
x=2
x+1=0
x+1-1=0-1
x=-1
Answer:
Step-by-step explanation:
8 cause 88-64=24(you have to distribute)
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
where
A = total amount in the account at the end of t years
r represents the interest rate
n represents the periodic interval at which it was compounded
p represents the principal or initial amount deposited
From the information given,
P = 11260
t = 6
r = 7.5/100 = 0.075
n = 52(Assuming the number of weeks in a year is 52 and it would be compounded 52 times in a year)
Thus, we have
A = 11260(1 + 0.075/52)^52*6
A = 11260(1 + 0.075/52)^312
A = 17653.5
