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slavikrds [6]
3 years ago
5

It is now 3:15 pm. Is it possible to drive 135 miles and arrive before 5:00 pm if ypu drove 55 mph? Explain your answer

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0
Well, how long will it take you to drive 135 miles at 55mph?

at 55 mph, you're doing 55 miles every hour, so we can simply get the quotient of 135/55 and that's how many hours it'll take you to drive 135 miles at that speed.

\bf \cfrac{135}{55}\implies \cfrac{27}{11}\implies 2\frac{5}{11}~hours\implies \textit{about 2hrs, 27 minutes}

so, it takes you that long, however, from 3:15 to 5:00pm there are only 45mins + 60mins or 1hr and 45 minutes, namely 1¾ hr.

so 2hrs and 27 minutes is much later than 1¾ hr, so, no dice, you can't arrive at 5pm, actually you'll arrive around 5:42pm.
Ilia_Sergeevich [38]3 years ago
4 0
From 3 pm to 5 pm is 2 hours, so you have less than 2 hours if you start at 3:15.

In two hours at 55 mph, you can drive 2×55 miles = 110 miles. It will take more than 2 hours to drive 135 miles at that speed.

Is it possible? NO
You cannot complete in less than 2 hours a trip that takes more than 2 hours to do.
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Phil has $6.00 he wants to buy creepy erasers that cost $1.05 each .if he buys 5 more they are 0.79 each does he have enough mon
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Answer:

No, he doesn't it would be 5 cents over the amount of money he has.

3 0
3 years ago
suppose that a certain basketball athlete earned $23,000,000 to play 80 games, each last 48 min. how much did the athlete earn p
Anit [1.1K]
He earns 23 000 000 per 80 games for 48min
Per game he earns
23000000 \div 8 0 = 782500
If he earns 782 500 per game he earns 5 989,5833 per minute

782500 \div 48 = 5989.5833
If he played 2/3 of the time he played 32min which means he earned...

782500 \div 32 = 24453.125
So he trained 35hours for a 48min match
Together that is 35.8hours

But I dont think this really matters here you just have to multiply 24453.125 with 60

And you get his hourly salary which is 1 467 187.5

5 0
3 years ago
Read 2 more answers
Given an example of a line that is parallel to y = 3x - 4
olga_2 [115]

Answer:

? i had this but forgot it sorry

Step-by-step explanation:

6 0
3 years ago
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I need help with this please!! ​
vovangra [49]

Answer:

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Step-by-step explanation:

1. Expand by distributing sum groups.3x( {2x}^{2}  + 5x - 1) - 3( {2x}^{2}  + 5x - 1)

2. Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - 3( {2x}^{2}  + 5x - 1)

3.Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - ( {6x}^{2}  +  15x - 3)

4. Remove parentheses.

{6x}^{3}  +  {15x}^{2}  - 3x -  {6x}^{2}  - 15x + 3

5. Collect like terms.

{6x}^{3}  +  {15x}^{2}  -  {6x}^{2} ) + ( - 3x - 15x) + 3

6. Simplify.

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Thus. the answer is,

{6x}^{3}  +  {9x}^{2}  - 18x + 3

5 0
2 years ago
Please help me with this question!!!!!
Naddika [18.5K]

Answer:

7/25

Step-by-step explanation:

θ lies in quadrant ii

so 2θ lies in quadrant iv

csc θ=5/3

sin θ=3/5 (sin θ=1/csc θ)

[cos(α+β)=cosαcosβ-sinαsinβ]

cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ

=1-2 (3/5)²

=1-2(9/25)

=1-18/25

=(25-18)/25

=7/25

5 0
3 years ago
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