Answer:
(6x - 1) • (2x + 9)
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
((22•3x2) + 52x) - 9
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 12x2+52x-9
The first term is, 12x2 its coefficient is 12 .
The middle term is, +52x its coefficient is 52 .
The last term, "the constant", is -9
Step-1 : Multiply the coefficient of the first term by the constant 12 • -9 = -108
Step-2 : Find two factors of -108 whose sum equals the coefficient of the middle term, which is 52 .
-108 + 1 = -107
-54 + 2 = -52
-36 + 3 = -33
-27 + 4 = -23
-18 + 6 = -12
-12 + 9 = -3
-9 + 12 = 3
-6 + 18 = 12
-4 + 27 = 23
-3 + 36 = 33
-2 + 54 = 52 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 54
12x2 - 2x + 54x - 9
Step-4 : Add up the first 2 terms, pulling out like factors :
2x • (6x-1)
Add up the last 2 terms, pulling out common factors :
9 • (6x-1)
Step-5 : Add up the four terms of step 4 :
(2x+9) • (6x-1)
Which is the desired factorization
HOPE IT HELPS! :))
Answer:
D
Step-by-step explanation:
First, let us figure out what is graphed and then manipulate each answer to try to match it.
The one with a positive slope is

The one with the negative slope is

Now that we have our graphed system of inequalities, we can try to match them to an answer.
A. while the x-2 is the same, the other does not have an x, so it cannot match.
B. The second inequality has the wrong sign, so it is impossible for this to be our answer.
C. When each of these are solved for y, you get
. Neither of these match so this cannot be correct.
D. When the first inequality is solved you get 
When the second inequality is solved you get 
As both of these answers match our graphed inequalities, D is the correct answer.
Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Answer:

Step-by-step explanation:
The given system is:


Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.
This gives me the system:


We could solve the first equation for
and replace the second
with that.
Let's do that.

Subtract
on both sides:

So we are replacing the second
in the second equation with
which gives us:





Now recall the first equation we arranged so that
was the subject. I'm referring to
.
We can now find
given that
using the equation
.
Let's do that.
with
:



So the solution is (8,-1).
We can check this point by plugging it into both equations.
If both equations render true for that point, then we have verify the solution.
Let's try it.
with
:


is a true equation so the "solution" looks promising still.
with
:


is also true so the solution has been verified since both equations render true for that point.