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3 years ago

How to solve -3(1+6r)=14-r

Mathematics

1 answer:

ahrayia [7]3 years ago

6 0

The answer is r= -1

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Answer:

<u><em>Rotation and Revolution are two motions of the earth.</em></u>

Step-by-step explanation:

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3 years ago

Write a problem in which $180 would be a reasonable answer

ad-work [718]

Answer: Word problem: Mya goes to a carnival and buys food for her and her friends. She buys 5 funnel cakes that were $20 each. She buys 10 buckets of popcorn that were 8 dollars each.

Regular problem: $20+$15+$20+$100+$25=180

Step-by-step explanation: I didn't know what you needed. I'm sorry if that's not it, but hope it helps.

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2 years ago

Science 8th grade 10 pts

Firdavs [7]

Answer:

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Step-by-step explanation:

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3 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Anastasy [175]

Answer:

$\frac{(a-b)^2+b^2}{a^2}$

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

$=\sqrt{(a-b-0)^2+(0-b)^2}$

$=\sqrt{(a-b)^2+b^2}$

Thus the area of the inner square = (side)²

$=(\sqrt{(a-b)^2+b^2})^2$

$=(a-b)^2+b^2\text{ square cm}$

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

$=\sqrt{(a-0)^2+0^2}$

$=\sqrt{a^2}=a$

Thus, the area of the outer square = (side)²

$=a^2\text{ square cm}$

Hence, the ratio of the area of the inner square to the area of the outer square

$=\frac{(a-b)^2+b^2}{a^2}$

4 0

3 years ago

Read 2 more answers

Please help me! I’ll name you brainiest!!!

Kamila [148]

Answer:

Step-by-step explanation:

first, put in (5x-4) for the x in g(x).

g(f(x))=(5x-4)^2 -1

now, FOIL and simplify.

25x^2-40x+16-1

25x^2-40x+15

now, plug in -1 for x.

25(-1)^2-40(-1)+15

25+40+15

8 0

3 years ago

Read 2 more answers