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Brums [2.3K]
3 years ago
10

How to solve -3(1+6r)=14-r

Mathematics
1 answer:
ahrayia [7]3 years ago
6 0
The answer is r= -1
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15 = -4p + 7<br><br><br> solving equation
Ratling [72]

Answer:

p = -2

Step-by-step explanation:

15 = -4p + 7

4p + 15 = 7

4p + 15 - 15 = 7 - 15

4p = -8

4p/4 = -8/4

p = -2

8 0
3 years ago
Read 2 more answers
A track runner is eager to see if practicing helps her improve. She has plotted data on her weekly 100-meter dash times (s) as w
insens350 [35]

Answer:

\displaystyle s = -\frac{1}{5}h + 20

Step-by-step explanation:

<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a \displaystyle -\frac{1}{5}<em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of \displaystyle [0, 20],so we choose this answer choice.

I am joyous to assist you anytime.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E3_t%7B%7Cx%2B2%7C%7D%20%5C%2C%20dx%20" id="TexFormula1" title=" \int\limi
photoshop1234 [79]
\displaystyle\int_{-3}^3|x+2|\,\mathrm dx

Recall the definition of absolute value:

|x|=\begin{cases}x&\text{for }x\ge0\\-x&\text{for }x

So we can split up the integration interval at x=-2 and apply this definition to rewrite the integral as

\displaystyle\int_{-3}^{-2}(-(x+2))\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx
=\displaystyle-\int_{-3}^{-2}(x+2)\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx
=-\left(\dfrac12x^2+2x\right)\bigg|_{x=-3}^{x=-2}+\left(\dfrac12x^2+2x\right)\bigg|_{x=-2}^{x=3}
=\dfrac12+\dfrac{25}2=13
7 0
3 years ago
Which statements are true about the ordered pair (7, 19) and the system of equations?
svp [43]
Explain it more so I can answer it
8 0
3 years ago
Postulate or theorem can be used to prove th ABC= AEDC. D A. SSS O B. ASA C. AAS D. SAS​
telo118 [61]

Answer:

sas

Step-by-step explanation:

4 0
3 years ago
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