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Kazeer [188]
3 years ago
11

After being dropped a certain ball always bounces back to 2/5 of the height of its previous bounceAfter the first bounce it reac

hes a height of 125 inchesHow high (in inches) will it reach after its fourth bounce?
A20
B15
C8
D5
E3.2
Mathematics
1 answer:
kap26 [50]3 years ago
8 0

Answer:

8 inches.

Step-by-step explanation:

In the first bounce, the height that the ball reaches was 125 inches.

If the ball always bounces back to \frac{2}{5} of the height, then after 2nd bounce it will reach (125 \times \frac{2}{5}) = 50 inches height.

Again, after 3rd bounce, it will reach (50 \times \frac{2}{5}) = 20 inches height.

And, after 4th bounce, it will reach (20 \times \frac{2}{5}) = 8 inches height. (Answer)

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3 years ago
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A sealed-tube manometer can be used to measure pressures below atmospheric pressure. The tube above the mercury is evacuated. Wh
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The <u>correct answers</u> are:

6.5 cm = 65.00001052 torr
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Explanation

The conversion rate from centimeters mercury (cm Hg) to torr is
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We have 6.5 cm; this means to convert we divide:
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