Hi there, just do 15/12*100% and that would equal 125%
Answer:
-0.05
Step-by-step explanation:
This will become much easier if we can get the ugly decimal into a nice fraction form.
Start by recognising 
. This is almost correct except the fraction is out by some number of factors of 10 (because the 125 part is correct but the number of 0s isn't).
And hence we see that 
and now the cube root becomes easy to compute:
![\sqrt[3]{-0.000125} = \sqrt[3]{\frac{-1}{8000}} = \frac{\sqrt[3]{-1}}{\sqrt[3]{8000}} = \frac{-1}{20} = -0.05](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-0.000125%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B-1%7D%7B8000%7D%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B-1%7D%7D%7B%5Csqrt%5B3%5D%7B8000%7D%7D%20%3D%20%5Cfrac%7B-1%7D%7B20%7D%20%3D%20-0.05)
.
Advanced: You ask for <em>all </em>real cube roots. however the function ![y=\sqrt[3]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx%7D)
is described as <em>bijective</em>. This means for all x, there is only one y corresponding to it. (And also for all y there is only one x corresponding to that). This means there can only ever be one cube root of any real number.
Answer:
B
Step-by-step explanation:
Because the number of tables have to be less then 140 and you have to multiply to find the number of small tables that can fit
Answer:
1,333 frogs
Step-by-step explanation:
okay so we know that mass remains conserved no matter where you are.
same here ^^
if the total mass of brass is 200 kg
the total mass of the new frogs formed from it when put together will be the same :)
and if there were n such frogs formed
we have,
total mass = n × mass of each frog
200 = n × 3/ 20
n = 4000/ 3
so it becomes something like 1,333.33
that is nearly 1,333 frogs can be made out of 200 kg of brass each weighing 3/ 20kg (the last ones a bit less to make upto 200kg)
