6 hours in the morning (from 6 am to 12 am)
1:45 in the afternoon (from 12 am to 1:45 pm)
sum
6:00 + 1:45 =
7:45 ( 7hours and 45 minutes)
Given the basis β={(1,−1,3),(−3,4,9),(2,−2,4)}β={(1,−1,3),(−3,4,9),(2,−2,4)} and x=(8,−9,6)x=(8,−9,6), I am to find the corresponding coordinate vector [x]β[x]β. I claim that the coordinate vectors entries x1,x2,x3x1,x2,x3 meet the following criterion:
x1(1,−1,3)+x2(−3,4,9)+x3(2,−2,4)=(8,−9,6)x1(1,−1,3)+x2(−3,4,9)+x3(2,−2,4)=(8,−9,6)This is equivalent to solving the augmented matrix
⎡⎣⎢1−13−3492−248−96⎤⎦⎥[1−328−14−2−93946]which is row equivalent to
⎡⎣⎢100−31020−18−10⎤⎦⎥
Answer:
11:18
Step-by-step explanation:
Here, we are interested in calculating the ratio of diameter of ball A to that of ball B
what to do here is to ensure that both diameters have measurements that are same units.
Thus, mathematically;
44 mm to 7.2cm
But, mathematically;
10 mm = 1 cm
Thus 7.2cm = 7.2 * 10 = 72mm
Thus, our ratio becomes;
44:72
divide through be 4, we have
44/4 : 72/4
= 11 : 18
Answer:A)33m
B)32.86m/s
Step-by-step explanation:
Using the equation of motion
V^2=U^2-2aS
Where V=final velocity of the car=0
U=initial velocity=17m/s
a=deceleration=-12m/s^2
S= distance covered by car before stopping
Substituting into the equation
0=17^2-2×12×S
0=289-24S
24S=289
S=289/24
S=12m.
The distance between the car and the deer=45-12=33m
B) Using same equation
Distance,S is now 45m,which is the distance between the car and the deer.while deceleration remains same
V^2=U^2-2aS
0=U^2-2×12×45
U^2=1080
U=√1080
U=32.86m/s