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Crank
3 years ago
7

What would be a reason for using a workstation rather than a personal computer?

Computers and Technology
1 answer:
Pavlova-9 [17]3 years ago
4 0
You can easily organize your work space. also you may have more resources. hope this helps
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A7DF is the hexadecimal representation for what bit pattern?
kipiarov [429]

Answer:

1010 0111 1101 1111

Explanation:

A = 10 in decimal = 1010 in binary

7 = 7 in decimal = 0111 in binary

D = 13 in decimal = 1101 in binary

F = 15 in decimal = 1111 in binary

Therefore 0xA7DF = 1010 0111 1101 1111 in binary

6 0
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______ is a process that marks the location of tracks and sectors on a disk.
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Answer is c low level format
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When federal courts are evaluating digital evidence from computer-generated records, what exception is applied to hearsay?'
Sidana [21]

Answer:

Business-records exception

Explanation:

The Business-records exception which is also known as the Business Entry Rule, this is an exception to the evidentiary rule (which rules out hearsay from a trial) that permits business records to be admitted if the appropriate foundation is laid to show the document is dependable and can be relied upon.

5 0
3 years ago
Why were Redditors interested in "Mister Splashy Pants"?
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a

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3 0
2 years ago
Read 2 more answers
#Write a function called has_a_vowel. has_a_vowel should have #one parameter, a string. It should return True if the string #has
Vladimir [108]

Answer:

Here is code in java.

import java.util.*;

class Main

{

// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // scanner object to read input from user

       Scanner obj=new Scanner(System.in);

       System.out.println("please enter a string:");

       //read the string input

       String inp=obj.next();

       // call the function to check whether string has vowel or not

       Boolean res=has_a_vowel(inp);

       // printing the result

       System.out.println("string contains vowel."+res);

     

       

   }catch(Exception ex){

       return;}

}

 // method to check string has vowel or not

public static boolean has_a_vowel(String str)

{

 // find length of the string

    int len=str.length();

   

    Boolean flag=false;

     int i;

    for( i=0;i<len;i++)

    {

        char chh=str.charAt(i);

         // if string contains vowel then flag will be true

        if(chh=='a'||chh=='e'||chh=='i'||chh=='o'||chh=='u')

        {

            flag=true;

            break;

        }

    }

     //returning the result

    return flag;

}

}

Explanation:

Create a scanner class object to read the string and assign it to variable

"inp".Call the function "has_a_vowel" with a string parameter.In this function

find the length of string and travers the string.If there is any vowel character

in the string then flag will be set to true otherwise flag will be false. Then it will

return the value of flag.We can test the function from the main by passing a string parameter.

Output:

please enter a string:                                                                                                                                        

vjcavcavacvajjfd                                                                                                                                              

string contains vowel:true

please enter a string:                                                                                                                                        

sdfdhgjkhltyrqwzxcvbmm                                                                                                                                        

string contains vowel: false                                                                                                                                  

                             

8 0
3 years ago
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