Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10 and 4
Given :
Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.
Let a and b be the two unknown numbers
Lets frame equation using the given statements
Twice the sum of a number and 3 times a second number is 4.
the difference of ten times the second number and five times the first is 90
Now use these two equations to solve a and b
Add both the equations
Now find out 'a'
The two numbers are -10 and 4
Learn more : brainly.com/question/13856304
So I think you’re asking for the solution to the equation mentioned.
The answer would be 4b-5
Explanation:
Steps:
4(b-6)+19
4b-24+19
4b-5 (Answer)
Answer:
15, d
Step-by-step explanation:
The absolute value of |-11| + |4| is 11+4 which is 15
Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:
648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then
There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651
Answer:
75 %
Step-by-step explanation:
To solve for the above question,
The percentage of pupils that submitted their project on time
= Number of pupils that submitted their project on time/Number of pupils × 100
Number of pupils that submitted their project on time = 30 pupils
Number of pupils = 40 pupils
= 30/40 × 100
= 75 %
The percent of the pupils that submitted their project on time is 75%
