Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
So multiply 20000 by 0.35, and you get 7000 grams.
With a gram to pound conversion (about 1 gram = 0.022 pounds), you'll get
about 15.43 pounds...
Answer:
C, x + 20 = 41
Step-by-step explanation:
X represents the number of small sea shells that we originally had. When the family adds 20 more shells, that makes x + 20. The total number is 41, so that means the number of sea shells they already had (x) plus the number of sea shells they collected (20) equals the number of shells they have now (41).
(0, 5), (1, 1 ), ( - 1, 9 )
to test the points substitute the x-coordinate into the equation and if the value is equal to the y- coordinate then it is an ordered pair
(0, 5 ) → y = 0 + 5 = 5 ← ordered pair
(1, 1 ) → y = - 4 + 5 = 1 ← ordered pair
(- 1, 9 ) → y = 4 + 5 = 9 ← ordered pair
( - 1, - 1 ) → y = 4 + 5 = 9 ← not an ordered pair
( - 1, - 9 ) → y = 4 + 5 = 9 ← not an ordered pair
(1, - 1 ) → y = - 4 + 5 = 1 ← not an ordered pair
(- 1, 1 ) → y = 4 + 5 = 9 ← not an ordered pair
