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3 years ago

13

The owner expects customers will be equally likely to order chocolate yougurt as vanilla yogurt. Based on this assumption, what

is the theorical probability a customer will choose vanilla yogurt?

1 answer:

AfilCa [17]3 years ago

5 0

The answer would be a fifty percent chance

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Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

Vikentia [17]

Answer:

StartFraction 16 over 81 EndFraction

Step-by-step explanation:

There are 4 prime numbers from 2 to 10 (2, 3, 5, 7) and 9 numbers from 2 - 10. Total possibilities: 9 * 9 = 81

Prime possibilities: 4 * 4 = 16

Therefore the answer is 16/81 or StartFraction 16 over 81 EndFraction

8 0

3 years ago

Read 2 more answers

I need help with 5 and 6 please

Yakvenalex [24]

Step-by-step explanation:

since both spinners are independent from each other, we can directly multiply their probabilities for the combined event.

1)

1/5 × 1/3 = 1/15

2)

1/5 × 2/3 = 2/15

3)

2/5 × 1/3 = 2/15 (you got that wrong on your paper)

4)

2/5 × 2/3 = 4/15

5)

3/5 × 1/3 = 3/15 = 1/5

6)

3/5 × 2/3 = 6/15 = 2/5

5 0

2 years ago

In a particular large Midwest city, a simple random sample of 400 people reveals that 128 of them know how to ski. 1. A 99.8% co

allsm [11]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

5 0

3 years ago

Read 2 more answers

HELP WILL GIVE BRAINLIEST!!

Vikentia [17]

Answer:

160 in^2

Step-by-step explanation:

5 0

3 years ago

If a/b and c/d are rational expressions, then what is a/b•c/d = a/b•c/b

Effectus [21]

Given:

$\frac{A}{B} \text { and } \frac{C}{D}$ are rational expressions.

$$\frac{A}{B} \cdot \frac{C}{D}=\frac{A \cdot D}{B \cdot C}$

To find:

The given statement is true or false.

Solution:

$\frac{A}{B} \text { and } \frac{C}{D}$ are rational expressions.

$$\frac{A}{B} \cdot \frac{C}{D}$

Multiply the numerators and multiply the denominators.

$$\frac{A}{B} \cdot \frac{C}{D}=\frac{A \cdot C}{B \cdot D}$

It is the correct answer.

Therefore, $\frac{A}{B} \cdot \frac{C}{D}=\frac{A \cdot D}{B \cdot C}$ is false.

4 0

3 years ago