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Soloha48 [4]
4 years ago
12

A building manager installs sensors to see how often people turn of the lights when they leave a room. After a month the manager

has sample size of 625, a sample mean of 47%, and a sample standard deviation of 5%. What is the confidence level for a confidence interval of 46.8% to 47.2%?
Mathematics
2 answers:
RideAnS [48]4 years ago
5 0

Answer:

The confidence level for a confidence interval of 46.4% to  47.6% is 99.7%.

Explanation:

First of all, the choices for this question are missing so I will include the ones I found for this exact question. The missing options are as follows:

A. 85% B. 95% C. 68% D. 99.7%

When it comes to statistics, a confidence interval (CI) is  a type of interval estimate  of a population parameter. Statistics is all about drawing conclusions in the face of uncertainty. Whenever you take a sample, you can’t be completely certain that your sample truly reflects the population it’s drawn from.

In conclusion, from the choices presented, the best option is the last one. Option D.


Aleks [24]4 years ago
3 0

Answer:

For apex the answer is 68%

Step-by-step explanation:

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An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?
Rasek [7]

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection across the axes

  • If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ f(x)=6(\frac{1}{3})^{x}

∵ g(x) is the image of f(x) after reflection across the y-axis

- From the rule above reflection across the y-axis changes the sign of x

∴ g(x)=6(\frac{1}{3})^{-x}

∵ (a)^{-n}=(\frac{1}{a})^{n}

∵ (\frac{1}{a})^{-n}=(a)^{n}

∴ (\frac{1}{3})^{-x}=(3)^{x}

∴ g(x)=6(3)^{x}

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
A store has 263 board games. Sit has 100 fewer puzzles than board games. The store has 10 more action figures than puzzles. Writ
Yuri [45]

so is it has 100 puzzles less than board games and you have 263 board games just subtract 263-100 which is 163. if it has 10 more action figures than puzzles and you have 163 puzzles you would add 10 to 163 which would give you 173 action figures.

163 puzzles and 173 action figures is the answer

4 0
3 years ago
Read 2 more answers
What is 0.95 × 3.75?
Alborosie
The answer is 3.5625
6 0
3 years ago
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The image is the result of an isometric transformation of its pre-image because _____.
Allisa [31]
They gave you the lengths showing each side of the original triangle is congruent to each side of the new triangle. There is no information to show if the triangle was rotated or reflected, so although it is possible that it was, we can't really tell. All we know is the triangles are congruent.  
5 0
4 years ago
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