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3 years ago

PLEASE SHOW HOW YOU HOW OYUR ANSWER!!!!18≥5K+4K

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

5 0

Answer:

k≤2

Step-by-step explanation:

18≥5k+4k

Step 1: Simplify both sides of the inequality.

18≥9k

Step 2: Flip the equation.

9k≤18

Step 3: Divide both sides by 9.

/9≤18/9

k≤2

kobusy [5.1K]3 years ago

3 0

Answer:

2>k

Step-by-step explanation:

18<u>></u>5k+4k

18>9k [isolate k by dividing by 9]

2>k

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What is 925/1000 in simplest form

mojhsa [17]

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3 years ago

A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes

marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

$V = s^2h = 5324$

$h = 5324 / s^2$

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top $s^2$

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Total surface area $A = s^2 + 4sh$

We can substitute $h = 5324 / s^2$

$A = s^2 + 4s\frac{5324}{s^2}$

$A = s^2 + 21296/s$

To find the minimum of this function, we can take the first derivative, and set it to 0

$A' = 2s - 21296/s^2 = 0$

$2s = 21296/s^2$

$s^3 = 10648$

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$h = 5324 / s^2 = 5324 / 22^2 = 11$

4 0

3 years ago

Write a quadratic function to model the vertical motion for each situation, given h(t) equals negative 16t squared plus v0t+h0

Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

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h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

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