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3 years ago

1. Find the equation of the line that is parallel to the line y = 0.6x-3 and passes through the point (-2,2).

1 answer:

8 0

So the equation is parallel and the slope will be 2
y=0.6x+b
sub in(-2,2) for x and y to find b
2=0.6(-2)+b
2+1.2=b
b=3.2
therefore the equation is y=0.6x+3.2

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Read 2 more answers

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$\bf f(x)=ln(x-5)\qquad [6,8]\qquad \cfrac{df}{dx}=\cfrac{1}{x-5}\\\\
-----------------------------\\\\
\textit{mean value theorem}\qquad f'(c)=\cfrac{f(b)-f(a)}{b-a}\\\\
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f'(c)=\cfrac{1}{c-5}\qquad thus\quad \cfrac{1}{c-5}=\cfrac{f(8)-f(6)}{8-6}
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\cfrac{1}{c-5}=\cfrac{ln(3)-ln(1)}{2}\implies \cfrac{1}{c-5}=\cfrac{ln(3)-0}{2}
\\\\\\
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