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3 years ago

1. Find the equation of the line that is parallel to the line y = 0.6x-3 and passes through the point (-2,2).

1 answer:

8 0

So the equation is parallel and the slope will be 2
y=0.6x+b
sub in(-2,2) for x and y to find b
2=0.6(-2)+b
2+1.2=b
b=3.2
therefore the equation is y=0.6x+3.2

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3 years ago

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2 years ago

Which statement is correct?

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Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

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Step-by-step explanation:

Which statement is correct?

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2.3x10-5

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2.3x10-5

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(2.06 x 10-2x1.88x10-)>

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Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

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$2.3 \times 10^-^5 = 230,000$

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3 years ago

Question 3 (2 points

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3 years ago

Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of education the students r

BaLLatris [955]

<h2>Answer with explanation:</h2>

Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.

Given : Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of education the students receive.

Set hypothesis to test :

$H_0: p=0.39\\\\H_a :p\neq0.39$

Sample size : n= 1055

Sample proportion : $\hat{p}=\dfrac{466}{1055}=0.441706161137\approx0.44$

Critical value for 95% confidence : $z_{\alpha/2}=1.96$

Confidence interval : $\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

$0.44\pm (1.96)\sqrt{\dfrac{0.39(1-0.39)}{1055}}\\\\0.44\pm0.0299536805135\\\\0.44\pm0.03\\\\=(0.44-0.03, 0.44+0.03)\\\\=(0.41,\ 0.47)$

Since , Confidence interval does not contain 0.39.

It means we reject the null hypothesis.

We conclude that 95% confidence interval represents evidence that parents' attitudes toward the quality of education have changed.

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