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castortr0y [4]
3 years ago
13

Math is my favorite subject and then civics is and gym that's it nothing more and i'll will never stop liking those subject caus

e they are my favorite
Thank you so much everyone
Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
Ya no problem :).............
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These tables of values represent continuous functions. in which function will the y-values be the greatest for very large values
bonufazy [111]

Answer: I belive its A

Step-by-step explanation:

6 0
3 years ago
Write an equation of the line
Deffense [45]
(3,0) and (0,9)

Slope= (9-0)/(0-3)= -3

Line equals Y= -3x+9
4 0
3 years ago
Whats the awnser to y over 5 -6=8
ohaa [14]
Y=70 thats the answer
7 0
3 years ago
(07.06) What exponential function is the best fit for the data in the table?
UNO [17]
The last choice, f(x)=1/4(4ˣ⁻⁻¹)-4, is correct.

Substituting our values for x, we have:
f(2) = 1/4(4²⁻¹)-4 = 1/4(4¹) - 4 = 1/4(4) - 4= 1 - 4 = -3
f(3) = 1/4(4³⁻¹)-4 = 1/4(4²) - 4 = 1/4(16) - 4 = 4 - 4 = 0
f(4) = 1/4(4⁴⁻¹)-4 = 1/4(4³) - 4 = 1/4(64) - 4 = 16 - 4 = 12

All of the data points fit.
6 0
4 years ago
Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo
Anna11 [10]

I'll assume you're supposed to compute the line integral of \nabla f over the given path C. By the fundamental theorem of calculus,

\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)

so evaluating the integral is as simple as evaluting f at the endpoints of C. But first we need to determine f given its gradient.

We have

\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)

Differentiating with respect to y gives

\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

and we end up with

f(x,y)=-3\cos(xy)+C

for some constant C. Then the value of the line integral is -3\cos192+3\cos3.

8 0
4 years ago
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