Question

if there are 500 people in a population, and 150 are homozygous HbA/hba, 150 are homozygous hbs/hbs, and 200 are heterozygous hba/hbs, what is the frequency of the hba allele in that population

Answer 1

Answer:

$0.547$

Explanation:

Given -

Total Population - $500$

Individuals with homozygous HbA/hbA genotype - $150$

Individuals with homozygous hbs/hbs genotype -$150$

Individuals with heterozygous hba/hbs genotype -  $200$

Let us assume the given population is in Hardy Weinberg' equilibrium

The frequency of individuals in the given population with homozygous HbA/hba genotype is equal to number of individuals with homozygous HbA/hba genotype divided by total population.

$\frac{150}{500} \\= 0.3$

The frequency of hba allele is equal to

$\sqrt{0.3} \\= 0.5477$