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slega [8]
3 years ago
12

(2a - 3b + 5c) - (-3a - 7c)

Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Answer:

5a-3b+12c

Step-by-step explanation:

(2a - 3b + 5c) - (-3a - 7c)

Distribute the minus sign

2a -3b +5c +3a +7c

Combine like terms

5a-3b+12c

Sidana [21]3 years ago
3 0

Answer:5a -3b + 12c

Step-by-step explanation:

<em><u>Question: </u></em>

(2a - 3b + 5c) - (-3a - 7c)

<em><u>First step:</u></em>

Distribute negitive sign

(2a - 3b + 5c) + (3a + 7c)

<em><u>Second Step:</u></em>

Remove parenthesis

2a - 3b + 5c + 3a + 7c

<em><u>Third Step:</u></em>

Add like terms

<u><em>Final Answer:</em></u>

5a -3b + 12c

<!> Brainliest is much appreciated! <!>

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3 years ago
Insert grouping symbols in 5 x 2 + 8 - 4 - 2 so that its value is 15
Arlecino [84]
5×2+8-4+1=15
cause
5×2=10
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5 0
4 years ago
Find the co-ordinates of the mid-point of the line joining the points A(2, -5) and B(6, 9).
Trava [24]

Answer:(4, 2)

Step-by-step explanation:

midpoint is between the x and y blah blah

4 0
2 years ago
Help pls!! this is a presentation I’m doing in class and I NEED this completed rn, ASAP!!! . What I need is just the answers for
snow_lady [41]

15. 70° because a right angle is 90° and we have the angle of ADB which is 20°. So 90°-20°=70°.

16. 70° because angle PSQ is 60° and angle QSR is 10°. So 60°+10°=70°.

17. 55° because it says it in the explanation. I assume this is a typo and they meant to ask the measurement of ADC and in that case it would be 130° because angle ADB is 75° and angle BDC is 55°. 75°+55°=130°.

18. 40° because angle PSQ is a right angle which means it's 90°. So 130°-90°=40°.

19. 140° because angle ADB is 120° and angle BDC is 20° so 120°+20°=140°.

20. 125° because again it's in the explanation. But if it's a typo and they meant what is the measurement of PSQ then it is 50° because PSR is 125° and QSR is 75° so 125°-75°=50°.

Hope this helps! :)

5 0
3 years ago
Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).
koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}

Therefore,

\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...

hence the first four nonzero terms of the series are

\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12

6 0
3 years ago
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