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3 years ago

11

HURRY PLZ!

1 answer:

timama [110]3 years ago

7 0

Answer:

D

Step-by-step explanation:

$f^{-1}(x)$ means the inverse. The inverse is the function reflected over the y=x line. This means the values have been reversed. (x,y)-->(y,x). We are looking for a point that has reversed values from the table.

The table has (1.-5) so the inverse is (-5,1) or D.

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The large rectangle below represents one whole. What percent is represented by the shaded area?

pantera1 [17]

Answer: 44%

Step-by-step explanation:

11/25= 0.44= 44%

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2 years ago

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What is the conjecture sentence for the pattern 1, ,4, 9 ,16?

nexus9112 [7]

Answer:

Square numbers

Step-by-step explanation:

if 1 is squared, you get 1.

if 2 is squared, you get 4.

if 3 is squared, you get 9.

if 4 is squared, you get 16.

And thus square numbers.

8 0

3 years ago

aliya0001 [1]

905 = 9 hundreds + 0 tens + 5 ones
or 8 hundreds, 10 tens, 5 ones

425 = 4 hundreds, 2 tens, 5 ones

8 hundreds, 10 tens, 5 ones
4 hundreds, 2 tens, 5 ones
---------------------------------------subtract
4 hundreds, 8 tens, 0 ones = 480......(905 - 425 = 480)

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3 years ago

Does anybody know how to do Factor with distribution property (Variables) ?

____ [38]

Hope i was able to help

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3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago