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PolarNik [594]
3 years ago
15

What fraction plus what fraction that are the same equals to 3/4 シ

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer:

easy. 375/1000 + 375/1000 = 3/4

Step-by-step explanation:

divide 3/4 by two. Your answer should be 0.375.

Then you convert 0.375 into a fraction, which would be 375/1000

JulijaS [17]3 years ago
4 0
Couldnt it just be 1/4 + 2/4? If the denominators are the same they can be added
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1780 is the best answer

Step-by-step explanation:

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2 years ago
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What is the total of 9X56
Ivahew [28]

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504

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5 0
3 years ago
Please answer the question in the picture.
ASHA 777 [7]

Answer:

C.) The relationship is proportional

Step-by-step explanation:

If D is true, then it is not proportional, constants of proportionality must not include multuplting or subtracting from anything.

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3 years ago
Determine the midpoint between the two points x(4,-6) and y(-2,8)
ikadub [295]

Answer:

p(a, b) = (1, 1)

Step-by-step explanation:

Midpoint formula is

p(a, b)=(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} ) ---------------(1)

Here

(x_1, y_1) = (4, -6) \ \ \ and \ \ \ (x_2, y_2) = (-2, 8)

Substituting values in equation (1)

p(a, b)=(\frac{4 - 2}{2}, \frac{-6 + 8}{2} )

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6 0
3 years ago
Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs
Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

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AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

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AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

7 0
2 years ago
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