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3 years ago

12

Simplify

gn="absmiddle" class="latex-formula">
simplify the following radical expression

2 answers:

Murljashka [212]3 years ago

7 0

/16•3
This is the best I could come up with hope it helps

irina [24]3 years ago

5 0

Answer:

$4\sqrt{3}$

Step-by-step explanation:

$48\\\\=2*24\\\\=2*2*12\\\\=2*2*2*6\\\\=2*2*2*2*3\\\\=2^2*2^2*3\\\\\Rrightarrow \sqrt{48}\\\\=\sqrt{2^2*2^2*3}\\\\=2*2\sqrt{3}\\\\=4\sqrt{3}$

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What is the product?

viva [34]

Answer:

its C

Step-by-step explanation:

I hope this helps :)

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2 years ago

The difference between a number x and 3 is at least nine Write an inequality for the following sentence.

dybincka [34]

Answer:

3 - x ≥ 9

Step-by-step explanation:

At least in inequality means greater than or equal to (≥)

Difference in mathematics means subtraction

The difference between a number x and 3

3 - x

is at least nine

3 - x ≥ 9

The inequality for the sentence is

3 - x ≥ 9

6 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

What are the properties of real numbers?

expeople1 [14]

Https://mathbitsnotebook.com/Algebra1/RealNumbers/RNProp.html

3 0

2 years ago

Often sales of a new product grow rapidly at first and then level off with time. This is the case with the sales represented by

True [87]

Answer:

Here we have the function:

S(t) = 500 - 400*t^(-1)

Then the rate of change at the value t, will be:

S'(t) = dS(t)/dt

This differentiation will be:

S'(t) = -400/t^2

Then:

a) the rate of change at t = 1 is:

S'(1) = -400/1^2 = -400

The rate of change after one year is -400

b) t = 10

S'(10) = -400/10^2 = -400/100 = -4

The rate of change after 10 years is -4, it reduced as the years passed, as expected.

7 0

3 years ago