Answer: 21599373.37618
Step-by-step explanation:
Answer:
1/2
Step-by-step explanation:
We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.
Answer:
100
Step-by-step explanation:
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brainliest is appreciated only 1more to level up please help :)))
Answer:
Imfaooooooo
Step-by-step explanation:
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Hi there!
So we are given that:-
- tan theta = 7/24 and is on the third Quadrant.
In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.
Since we want to find the value of cos theta. cos must be less than 0 or in negative.
To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.
<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>I</u><u>d</u><u>e</u><u>n</u><u>t</u><u>i</u><u>t</u><u>y</u>

Substitute tan theta = 7/24 in.

Evaluate.

Reminder -:

Hence,

Because in QIII, cos<0. Hence,

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>y</u><u>t</u><u>h</u><u>a</u><u>g</u><u>o</u><u>r</u><u>e</u><u>a</u><u>n</u><u> </u><u>T</u><u>h</u><u>e</u><u>o</u><u>r</u><u>e</u><u>m</u>

Define c as our hypotenuse while a or b can be adjacent or opposite.
Because tan theta = opposite/adjacent. Therefore:-

Thus, the hypotenuse side is 25. Using the cosine ratio:-

Therefore:-

Because cos<0 in Q3.

Hence, the value of cos theta is -24/25.
Let me know if you have any questions!