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neonofarm [45]
2 years ago
8

Write an equation for the following real life scenario.

Mathematics
1 answer:
mojhsa [17]2 years ago
5 0

Answer:

1/2x = 16

x = 32

Step-by-step explanation:

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4x-2y=14
Blababa [14]
4x - 2y = 14
y = 0.5x -1

Get just one variable on one side for both equations.

4x - 2y = 14 ⇒ 4x = 2y + 14 ⇒ 4x - 14 = 2y
y = 0.5x - 1 ⇒ x - 2 = 2y

Use the transitive property and then solve for x.

x-2 = 4x-14
12 = 3x
x = 4

<em>Edit: Apprently I didn't use substitution. Oops! Sorry...</em>
4 0
3 years ago
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You are required to choose two topics from a list of five to write about on your science test. How many different pairings are p
marissa [1.9K]
A B C D E represent the subjects


A+A1

A+B2

A+C3

A+D4

A+E5

B+B6

B+C7

B+D8

B+E9

C+C10

C+D11

C+E12

D+D13

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7 0
3 years ago
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The perimeter of parallelogram ABCD is 46 inches. What is DA?
kvv77 [185]
I hope this helps you

5 0
2 years ago
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Write a possible third degree polynomial with integer coefficient that have zeros: 1 2i, -4. Assume the leading coefficient to b
jasenka [17]

Answer:

The polynomial is:

p(x) = x^3 + 2x^2 - 3x + 20

Step-by-step explanation:

A third degree polynomial can be written in function of it's zeros x_1, x_2, x_3 the following way:

p(x) = a(x - x_1)(x - x_2)(x - x_3)

In which a is the leading coefficient.

Integer coefficient that have zeros: 1+2i, 1-2i, -4

Leading coefficient: 1

So

p(x) = 1(x - (1+2i))(x - (1-2i))(x - (-4))

p(x) = (x - 1 -2i)(x - 1 + 2i)(x + 4)

p(x) = ((x-1)^2 - (2i)^2)(x + 4)

p(x) = (x^2 - 2x + 1 - 4i^2)(x + 4)

Since i^2 = -1

p(x) = (x^2 - 2x + 1 + 4)(x + 4)

p(x) = (x^2 - 2x + 5)(x + 4)

p(x) = x^3 + 4x^2 - 2x^2 - 8x + 5x + 20

p(x) = x^3 + 2x^2 - 3x + 20

3 0
3 years ago
Which equation would you use to solve the following situation?
lara31 [8.8K]
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