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2 years ago

What is true of a population in a statistical survey?

1 answer:

8 0

Answer:The actual population from which the survey data are collected, given the restrictions from data collection operations.

Step-by-step explanation:

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one angle has a measure that is less than 15 than two times a number. a second angle is three times the number. the angles are c

adell [148]

Answer:

27 degrees and 63 degrees

Step-by-step explanation:

Let n be the number.

Angle 1: 2n-15

Angle 2: 3n

If the angles are complementary they add up to 90.

Therefore we can write an equation.

2n-15+3n=90

Combine like terms

5n-15=90

Add 15 to both sides

5n=105

n=21

Now we plug 21 in for n and solve for the angles

Angle 1 = 2(21)-15

Angle 1 = 42-15

Angle 1 = 27

Angle 2 = 3(21)

Angle 2 = 63

4 0

1 year ago

What is the value of x?

Nata [24]

Answer:

Step-by-step explanation:

hypotenuse^2= leg^2 + leg^2

10^2= 6^2 + x^2

100= 36 + x^2

100-36= x^2

64= x^2

√64=√x^2

8= x

7 0

2 years ago

What is - 15 +6f = 5

Keith_Richards [23]

Answer:

f = 10/3

Step-by-step explanation:

-15 + 6f = 5

-15 + 15 + 6f = 5 + 15

6f = 20

6f/6 = 20/6

f = 20/6 = 10/3 = 3.333...

8 0

2 years ago

Read 2 more answers

Hi how are you this question use all my points

bonufazy [111]

Answer:

uhm hi- how are you doing today :) did you eat-?

3 0

2 years ago

Read 2 more answers

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago