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Tanya [424]
2 years ago
8

Pls answer and thanks!!

Mathematics
2 answers:
QveST [7]2 years ago
5 0
Y=-3,x=1 because of the work
Keith_Richards [23]2 years ago
3 0

Answer:

Problem:

Solve 3x−y=6;y=x−4

Steps:

I will try to solve your system of equations.

y=x−4;3x−y=6

Step: Solvey=x−4for y:

Step: Substitutex−4foryin3x−y=6:

3x−y=6

3x−(x−4)=6

2x+4=6(Simplify both sides of the equation)

2x+4+−4=6+−4(Add -4 to both sides)

2x=2

2x

2

=

2

2

(Divide both sides by 2)

x=1

Step: Substitute1forxiny=x−4:

y=x−4

y=1−4

y=−3(Simplify both sides of the equation)

Answer:

y=−3 and x=1

Step-by-step explanation:

Hope this helped you

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Please help me thank u so much
alex41 [277]

Answer:

28/5= 5 3/5 15/7= 2 1/7 21/4=5 1/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the equation of the graph below?°
MAVERICK [17]

Answer:

the first formula

Step-by-step explanation:

the graph is y=cosx and cosx=sin(x+90)

8 0
3 years ago
How many zeros are in the product of any nonzero whole number and 1000?Explain your answer
kotegsom [21]

Answer:

At least 3.

Step-by-step explanation:

It depends on the  whole number.

For example 53 * 1000 = 53,000 (3 zeros).

101 * 1000 = 101,000  (4 zeros).

8 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
2 years ago
Please help me asap!!!
ololo11 [35]

G should be the correct answer

Hope this helps!

4 0
3 years ago
Read 2 more answers
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