In y = mx + b form, which is what ur equation is in, the y int can be found in the b position
y = mx + b
y = x + 6
as u can see, the number in the b position, ur y int, is 6 <==
Answer:
- 15x² + 7x + 1
Step-by-step explanation:
Given
2x² - 9 - 17x² + 10 + 7x ← collect like terms
= (2x² - 17x² ) + 7x + 1
= - 15x² + 7x + 1
204 /6 = 34
29 +31 +33 + 35 +37 +39 = 207
4th number = 35
The First is sec^2(x). Second is 2sec^2tanx. From that you get 2[2sec^2xtan^x+sec^4x]
Im pretty sure the answer id b