Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
It would be D, because to be a function, a set of ordered pairs cannot have the same x value. The y value can be the same though.
(5,6), (8,6), (9,6)
As you can see, all of the x values are different, so it is a function.
Answer:
B) 0.85
Step-by-step explanation:
By definition, complementary angles add to 90 degrees.
The given angle 58 degrees is complementary to 90-58 = 32 degrees. The two angles 58 and 32 add to 90.
Therefore, cos(32) = 0.848 = 0.85
Answer:
50
Step-by-step explanation:
The sum of a triangle's angles are 180 so since you know one angle is 80, you would put 2x + 80 = 180, which would be 2x = 100, which simplifies to x = 50
