Answer: OPTION A.
Step-by-step explanation:
Given the following function:
You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:
In this case:
Then, substituting values, you get:
Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>
Answer:
The ratio is 25:4
Step-by-step explanation:
Since JKLM ~ EFGH, the ratio of the areas of JKLM to EFGH is equal to the square of the ratio of their corresponding sides.
JK corresponds to EF
JK/EF = 20/8 = 5/2
Therefore:
the ratio of the areas of JKLM to EFGH = 5² : 2²
The ratio = 25:4
Multiply
ignoring the square root sign for a moment to get
. Simplify
to get 20. so, your answer is B.
You can use a calculator, put them in and you can get the answers easily.
1.204-(-36)=240
2.)87+(-96)=-9
3.)-12x3=-36