Question

HURRY!!! 18 POINTS!!!

Answer 1

1. you must use the following equation to resolve this problem, (x-h)^2 = 4p(y-k) where the verte of the parable is the point ( h, k) and it is given in the exercise
2. The directrix is ​​therefore the horizontal line   that passes through the point ( o, -p)  and the   the distance between the vertex and the focus is called  focal distance  and it is  equal p
3. in this exercise, p = 1 + 1/2 = 1,5
4. then substitute the values  in the equation given
5. (x-1)^2  =4(3/2)(y-1) =  (x-1)^2= 6(y-1)