Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N(
)' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N()' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.
Formula for probability of an event E can be observed as:
So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
All exterior angles of n-gon always add up to 360°
To find the number of sides:
Correct choice is 1,260 and 151,200
The product of 252 and 605 is 152,460
In the choice we have to choose from, one or more numbers have to add up to give a total of 152,460.
The choice is actually 1,260 and 151,200 which gives a total of <u>152</u><u>,</u><u>460</u><u>.</u>
Answer:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Step-by-step explanation:
We have these following probabilities:
An 88% probability that the day is cloudy.
An 54% probability that the day is both foggy and cloudy.
What is the probability that a randomly selected day in November will be foggy if it is cloudy?
This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
