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Misha Larkins [42]
3 years ago
10

What time I will be in 67 minutes

Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

F. 5:27

Step-by-step explanation:

4:20+67 minutes= 5:27

velikii [3]3 years ago
7 0

Answer: F 5:27

Step-by-step explanation: the clock shows 4:20. If you add 60 minutes to that it brings the hands all the way back around. Making the time 5:20. Then add the extra 7 minutes making it 5:27.

Hope this helped

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HELP PLSSS 20 POINTS!!! ASAP
sukhopar [10]

Answer:

60

Step-by-step explanation:

did this before so easy

7 0
3 years ago
Read 2 more answers
What is the slope of the line that contains the points (-4, 2) and (6, -3)?
mote1985 [20]

Answer:

-1/2 or -\frac{1}{2}

Step-by-step explanation:

to find the slope, use the formula

(y₁ - y₂)/(x₁ - x₂)

(2 - -3)/(-4 - 6)

(2 + 3)/(- 4 - 6)

5/-10

1/-2

-1/2

8 0
3 years ago
-25 = -4r + 5 please help
Andrej [43]
-25=-4r+5
Subtract 5 to each side
-25-5=-4r+5-5
-30=-4r
Divided -4 to each side
-30/-4=-4r/-4
7.5=r
Check:
-25=-4r+5
Substitute r with 7.5
-25=-4(7.5)+5
-25=-30+5
-25=-25. As a result, r=7.5. Hope it help!
6 0
3 years ago
Read 2 more answers
Taxi A charges a fee of $3.50, plus $1.75 per mile. Taxi B charges a few of $1.25, plus $2.00 per mile. At what distance would t
frez [133]
Taxi A
1mile £3.50+£1.75=£5.25
Taxi B
1mile £1.25+£2.00=£3.25

Taxi A
2miles £3.50+£3.50=£7.00
Taxi B
2miles £1.25+£4.00=£5.25

Taxi A
3miles £3.50+£5.25=£8.75
Taxi B
3miles £1.25+£6.00=£7.25

Taxi A
4miles £3.50+£7.00=£10.50
Taxi B
4miles £1.25+£8.00=£9.25

Taxi A
5miles £3.50+£8.75=£12.25
Taxi B
5miles £1.25+£10.00=£11.25

Taxi A
6miles £3.50+£10.50=£14.00
Taxi B
6miles £1.25+£12.00=£13.25

Taxi A
7miles £3.50+£12.25=£15.75
Taxi B
7miles £1.25+£14.00=£15.25

Taxi A
8miles £3.50+£14.00=£17.50
Taxi B
8miles £1.25+£16.00=£17.25

Taxi A
9miles £3.50+£15.75=£19.25 (the same)
Taxi B
9miles £1.25+£18.00=£19.25 (the same)

^^^
They would have to drive 9 miles for the taxi to cost the same.

Hope this helped, this is the longest way to work it out but also the simplest.
6 0
3 years ago
Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard devia
EleoNora [17]

Answer:

0.961

Step-by-step explanation:

To answer this, find the area under the standard normal curve to the left of 130 pounds:

Using the function normalcdf( on a TI calculator, we get:

normalcdf(-1000, 130, 100, 17) = 0.961

8 0
3 years ago
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