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Salsk061 [2.6K]
3 years ago
14

What is 2÷413= what and a stratagy

Mathematics
2 answers:
bearhunter [10]3 years ago
7 0

206.5 you would use a calculator

deff fn [24]3 years ago
6 0

0.0048426150121065 is the answer for that

its pure division


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One angle of an isosceles trapezoid has measure 57. What are the measures of the other angles?
Kobotan [32]
\alpha =57^o\\ \\ The \ interior \ angle \ at \ the \ shortest \ base \ is \ equal \ to :\\ \\ \beta = 180^o - 57^o = 123^o



3 0
3 years ago
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June needs 45 gallons of punch for a party and has 2 different coolers to carry it in. The bigger cooler is 5 times as large as
mixer [17]

Answer:

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

Step-by-step explanation:

Let smaller cooler's capacity be x gallons

Hence

Larger cooler's capacity will be 5x gallons

Together, they will hold 45 gallons, thus we can write:

x + 5x = 45

Solving:

x + 5x = 45

6x = 45

x = 45/6 = 7.5

And 5x = 5(7.5) = 37.5

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

4 0
3 years ago
The ratio of men to women working for a company is 3 to 4. If there are 112 women working for the company, what is the total num
Andrews [41]
112 / 4 = 28

28 x 3 = 84

There are 84:112 men to women working for the company.
3 0
3 years ago
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Help?!?!?!!?!?!?! :)
Andru [333]

Answer:

I think its

Step-by-step explanation:

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3 0
3 years ago
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the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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