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4 years ago

-2(8p+2)-3(2-7p)-2(4+2p)=0

Mathematics

1 answer:

zysi [14]4 years ago

8 0

-2(8p+2)-3(2-7p)-2(4+2p)=0

mutiply the first bracket by -2

(-2)(8p)= -16p

(-2)(+2)= -4

mutiply the second bracket by -3

(-3)(2)= -6

(-3)(-7p)= 21p

mutiply the third bracket by -2

(-2)(4)= -8

(-2)(+2p)= -4p

-16p-4-6+21p-8-4p= 0

-16p+21p-4p-4-6-8= 0 ( combine like terms)

5p-4p-4-6-8= 0

p-4-6-8= 0

p-10-8= 0

p-18= 0

move -18 to the other side to get p by itself

sign changes from -18 to +18

p-18+18= 0+18

p= 0+18

Answer: p= 18

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2 years ago

The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num

Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

$n = \dfrac{565}{20} = \mathbf{28.25}$

Rounding down to the nearest whole number, we have;

The number of uniforms the school can buy, n = 28 volleyball uniforms.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

20 represents a $20 price per uniform.

3. The 35 in the equation represents an initial flat fee, such as an

ordering or initial fee, which is fixed.

Therefore;

The number 35 represent the fixed cost for producing the uniforms

4. The price per uniform of $30 changes the coefficient of n from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

$n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}$

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

The school can purchase 10 fewer uniforms at $30 per uniform

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2 years ago

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3 years ago

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Answer:

The point is (15,10)

Step-by-step explanation:

Given data:

cost of card $50

x card sold for $2

y card sold for $1.50

from the above information given above we have following relation

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the above equation is linear, therefore to find the point to point out the number of card sold, hit and try method should be used. select the proper point (x, y) so that after putting in above equation there result must not be greater than 50

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4 years ago

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10
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3 years ago