Answer:
Step-by-step explanation:
Suppose we think of an alphabet X to be the Event of the evidence.
Also, if Y be the Event of cheating; &
Y' be the Event of not involved in cheating
From the given information:



Thus, 
P(Y') = 1 - 0.01
P(Y') = 0.99
The probability of cheating & the evidence is present is = P(YX)



The probabilities of not involved in cheating & the evidence are present is:


(b)
The required probability that the evidence is present is:
P(YX or Y'X) = 0.006 + 0.000099
P(YX or Y'X) = 0.006099
(c)
The required probability that (S) cheat provided the evidence being present is:
Using Bayes Theorem



Answer:
tan cox³ / 5s
Replace ^-1 with ^(-1)
Replace x3 with x³
<h3>Step 1</h3>
Simplify
x³ / 5
Use equation to solve
tan • ((co • (s-1)) • x³ / 5)
<h3>Step 2</h3>
Take the previous equation and format it in a simpler form
tan • ((co • (s-1)) • x³ / 5) ⇒ tan • cox³ / 5s
<h3>Result</h3>
tan cox³ / 5s
Answer: 2 dollers for each can of tuna
Step-by-step explanation: 2 x 3 = 6 or 2 + 2 + 2 = 6
X + y = 304,250
x = y + 51,000
Plug in (y+51,000) for x into the first equation
y+51,000+y = 304,250
Subtract 51,000 from both sides.
2y = 253,250
y = 126,625
Plug y into second equation
x = 126,625 + 51,000
x =177,625
Person A : 177,625
Person B : 126,625