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MAVERICK [17]
3 years ago
12

A non-profit organization is having a couple’s fundraiser. The banquet hall will only hold 250 people. The President, Vice-pres

ident, two volunteers, and a guess speaker will be working the event. How many couples will be able to attend the banquet? (Pls help me solve the equation)

Mathematics
1 answer:
marta [7]3 years ago
7 0
Answer: 122
Explanation: 250 - 5 = 245
(The 5 comes from the president, Vice President, two volunteers, and guess speaker)
245/2 = 122.5
Half a couple cannot attend so the answer would be 122 couples can attend
You might be interested in
Elena receives ​$131 per year in simple interest from three investments totaling ​$3000. Part is invested at​ 3%, part at​ 4% an
ioda

Answer:

Elena invested $ 1,700 at 5%, $ 700 at 4%, and $ 600 at 3%.

Step-by-step explanation:

Given that Elena receives $ 131 per year in simple interest from three investments totaling $ 3000, and part is invested at 3%, part at 4% and part at 5%, and there is $ 1000 more invested at 5% than at 4%, to find the amount invested at each rate, the following calculations must be performed:

1500 x 0.05 + 500 x 0.04 + 1000 x 0.03 = 75 + 20 + 30 = 125

1600 x 0.05 + 600 x 0.04 + 800 x 0.03 = 80 + 24 + 24 = 128

1700 x 0.05 + 700 x 0.04 + 600 x 0.03 = 85 + 28 + 18 = 131

Therefore, Elena invested $ 1,700 at 5%, $ 700 at 4%, and $ 600 at 3%

7 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
CAN someone PLZ help !?
Trava [24]

no entiendo hingles......pero puedo puedo tener esos 5 puntos

6 0
2 years ago
Need help with this asap plz❤️
BigorU [14]

What question are you needed answers to?

6 0
3 years ago
How many times the size of 0.81 is 810
MAXImum [283]

Answer:

810 is 100 times the size of 0.81

8 0
3 years ago
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