Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
4x^5 + 3x + 1...the ^5 makes it a fifth degree....and the leading coefficient is 4
Step-by-step explanation:
2 things to remember for problems like this :
the sum of all angles in a triangle is always 180 degrees.
the law of sines :
a/sin(A) = b/sin(B) = c/sin(C) or upside-down (whatever fuss the situation better), with the sides being always opposite of the angles.
so, now for the given problems :
4.
x/sin(90) = 12/sin(29)
x/1 = x = 12/sin(29) = 24.75198408...
rounded x = 24.8
5.
the opposite angle of x is
180 - 90 - 16 = 74 degrees.
x/sin(74) = 37/sin(90) = 37
x = 37×sin(74) = 35.56668275...
rounded x = 35.6
6.
the opposite angle of x is
180 - 90 - 58 = 32 degrees.
x/sin(32) = 22/sin(58)
x = 22×sin(32)/sin(58) = 13.74712574...
rounded x = 13.7
7.
the opposite angle of 15 is
180 - 90 - 51 = 39 degrees.
x/sin(51) = 15/sin(39)
x = 15×sin(51)/sin(39) = 18.52345735...
rounded x = 18.5
