Answer:
she will buy 4 packs of pencils
Sample Size = n = 18
Proportion of processor which meet specifications = p = 90% = 0.90
We are given that the Binomial distribution is valid for the given case. The mean value of the binomial distribution can be calculated as:
Mean = np
Using the values of n and p for given case, we get:
Mean = 18 x 0.90 = 16.2
So, on average 16.2 processor will meet the specifications
Answer:
10
Step-by-step explanation:
1000 = 10 × 10 × 10 = 10³ , then
![\sqrt[3]{1000}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D)
= ![\sqrt[3]{10^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E3%7D)
= 10
3lb + 3x=18
3-3+3x=18-3
3x=15
3x/3=15/3
x=5
she can carry 5 books
Step-by-step explanation:
= - 4
= a* + (3- 1) d*
- 4 = a + 2d . . . . . . . . .(i)
= - 29
= a + ( 8 - 1) d
- 29 = a + 7d . . . . . . . . (ii)
subtracting equations (i) and (ii)
25 = 5d
d = -5
placing d = -5 in equation (i)
a - 10 = -4
a = 6
For an arithmetic Progtession
= a + (n - 1)d
= 6 + (n- 1)-5
= 6 - 5n + 5
![\underline {a_n = 11 - 5n }](https://tex.z-dn.net/?f=%20%5Cunderline%20%7Ba_n%20%3D%2011%20-%205n%20%7D)
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*![\boxed{ \mathfrak { d \:stands\: for\: common \: difference } }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cmathfrak%20%7B%20d%20%5C%3Astands%5C%3A%20for%5C%3A%20common%20%5C%3A%20difference%20%7D%20%20%7D%20)