1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zloy xaker [14]
3 years ago
12

Find all real and complex zeros of p(x)=x^3-x^2-4x-6​

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

x = 3 , -1 + \sqrt{-1} , -1 - \sqrt{-1}

Step-by-step explanation:

⇒ p(x)=x^{3} -x^{2} -4x-6

⇒ p(x)=(x-3)(x^{2} +2x+2)

now, for zeros of (x^{2} +2x+2),

⇒ x =  \frac{-b}{2a} ± \frac{\sqrt{b^{2}-4ac } }{2a}

⇒ x =  \frac{-2}{2} ± \frac{\sqrt{2^{2}-4(2) } }{2}

⇒ x = -1 ± \sqrt{-1}

hence, all the roots are,

x = 3, -1 + \sqrt{-1}, -1 - \sqrt{-1}

You might be interested in
Arnaud randomly selected 30% of French International Studies students and asked them if they know how to speak French. Of the st
daser333 [38]
The answer for this would be 110
4 0
3 years ago
3. Lonnie has a gift card worth $600 for a local entertainment store. Movies cost $20 each and newly released video games cost $
Mandarinka [93]

Answer:

8 movies and 6 video games

<em></em>

Step-by-step explanation:

Given

Gift\ Card = \$600

Movies =\ $20

Video\ Game = \$50

Minimum\ Items = 13

Required

Determine the items Lonnie can afford

To solve this question, we make use of trial by error method by taking the options one at a time:

Option 1: 6 movies and 4 video games

<em>This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.</em>

<em />

Option 2: 14 movies and 7 video games

Cost = 14 * \$20 + 7 * \$50

Cost = \$280 + \$350

Cost = \$630

<em>This option can not be considered because the cost of purchase is greater than Lonnte's worth of Gift card.</em>

<em />

Option 3: 2 movies and 10 video games

<em>This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.</em>

<em />

Option 4: 8 movies and 6 video games

Cost = 8 * \$20 + 6 * \$50

Cost = \$160 + \$300

Cost = \$460

Hence, the correct option is <em>8 movies and 6 video games </em>

4 0
3 years ago
The following table gives the mean scores for 4 different classes
aksik [14]

Answer:

a

Step-by-step explanation:

a

5 0
3 years ago
Read 2 more answers
HELP PLEASE! DUE TMR! Answer whichever ones you want and i can try to deal with the rest. I just have alot of work and need extr
Yuri [45]

Answers

1) 4

2) 0, 2, -10

3) 0, 5, -2

Step-by-step explanation:

1) x³ - 64 = 0

x³ = 64

x = 4

2) x³(x² + 8x - 20) = 0

x³(x² + 10x - 2x - 20) = 0

x³(x(x + 10) - 2(x + 10)) = 0

x³(x + 10)(x - 2) = 0

x = 0, 2, -10

3) x³ - 3x² - 10x = 0

x(x² - 3x - 10) = 0

x(x² - 5x + 2x - 10) = 0

x(x(x - 5) + 2(x - 5)) = 0

x(x - 5)(x + 2) = 0

x = 0, 5, -2

4 0
3 years ago
5 fifths × 3 fifteinths =?
Pachacha [2.7K]

Answer:

1/5 or 0.2 i hope this helped you

8 0
3 years ago
Other questions:
  • Is it possible to prove that the triangles are congruent?
    10·1 answer
  • Mahima deposited 178five hundred rupe note in the bank how much money did she deposited in the bank. 4rt class my bro needs answ
    7·1 answer
  • This net can be folded to form a cube with a side length of 20 units
    8·1 answer
  • Solve for x 6 (8X minus 1) equals 9 (x + 2)
    9·1 answer
  • If a bag contains 12 quarters, 6 dimes, and 18 nickles, what is the part-to-whole ratio of quarters to all coins?
    12·2 answers
  • The wings of the butterfly is 6.7 centimeters what is the wings of the buterfly in millimeters
    10·2 answers
  • GOT THESE FREAKING WORD PROBLEMS MAN I SUCK AT THESE THINGS PLS HELPPPPPPPP!!!! THERES MORE AFTER THIS TOOO!!!!!!!
    9·1 answer
  • Can somebody help me on this ?
    6·1 answer
  • 13. Find the perimeter.
    15·2 answers
  • QS∥PT. Complete the proof that m∠P+m∠T=m∠RQT without using the Triangle Angle Sum Theorem.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!