The perimeter of ABC with vertices A(-4,4), B(2,-2), and C(-4,-2) is 20.848 units.
We are given the vertices:
A(-4,4), B(2,-2), and C(-4,-2).
We need to find the perimeter of ABC.
AB = √ ( 2 + 4)² + (-2 - 4)²
AB = √ 6² + 6²
AB = √72
AB = 6 √2 units
BC = √ (-4 - 2)² + ( -2 + 2)²
BC = √ 6²
BC = 6 units
AC = √ ( -4 + 4)² + (-2 - 4)²
AC = √ 6²
AC = 6 units.
Perimeter = AB + BC + AC
Perimeter = 6 √2 + 6 + 6 units
Perimeter = 12 + 6 √2 units.
Perimeter = 12 + 6(1.414) units
Perimeter = 12 + 8.848 units
Perimeter = 20.848 units
Therefore, the perimeter of ABC with vertices A(-4,4), B(2,-2), and C(-4,-2) is 20.848 units.
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