All categories

3 years ago

Graph y+6=45(x+3) using the point and slope given in the equation

Mathematics

1 answer:

padilas [110]3 years ago

7 0

Answer:

Check attached graph of the line in picture

Step-by-step explanation:

We have been given an equation y+6=45(x+3) in point slope form.

It says to use the point and slope from given equation to create the graph.

So compare equation y+6=45(x+3) with point slope formula

y-y1=m(x-x1)

we see that m=45, x1=-3 and y1=-6

Hence first point is at (-3,-6)

slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).

Now we just graph both points (-3,-6) and (-2,39) and join them by a straight line. Final graph will look like the line in attached graph.

You might be interested in

What statement is true about f(x)=2x

inna [77]

Answer:

Subtract

from both sides of the equation.

(

)

−

Step-by-step explanation:

5 0

3 years ago

Solve this formula for the velocity for (d)<br><br> Show your work

Vinvika [58]

Answer:

d = vt

Step-by-step explanation:

Step 1: Write equation

v = d/t

Step 2: Multiply both sides by t

vt = d

Step 3: Rewrite

d = vt

7 0

2 years ago

Find the vertex of: y=6(x-1)2-8<br> (x,y)

Pepsi [2]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\begin{array}{lllcll}
y=&6(x-&1)^2&-8\\
&\uparrow &\uparrow &\uparrow \\
&a&h&k
\end{array}$

5 0

2 years ago

THANK YOU (PLEASE HELP) <3 C: TYSMMMM PLZZZ Write an equation of a parabola that is wider than the parent function, reflects

My name is Ann [436]

Answer:

y=-2x^2-4

Step-by-step explanation:

The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.

y = 2x^2

Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.

Final Equation: y=-2x^2-4

3 0

2 years ago

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.

Alborosie

Assume that the rule connecting height of the candle to time is a linear one. If you do, then we have to find the equation of this line, and then use this equation to predict the height of the candle after 11 hours.

Two points on this line are (6,17.4) and (23, 7.2). The slope is thus
7.2-17.4 -6
m = --------------- = ----------- or -3/5.
23-6 10

Find the equation of the line. I'm going to use the slope-intercept formula:

y = mx + b => 7.2 = (-3/5)(23) + b. Solving for b, b = 21.

Now we know that y = (-3/5)x + 21

Let x=11 to predict the height of the candle at that time.

y = (-3/5)(11) + 21 = 14.4 inches (answer)

7 0

3 years ago

Graph ​ y+6=45(x+3) ​ using the point and slope given in the equation

Graph y+6=45(x+3) using the point and slope given in the equation