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forsale [732]
3 years ago
13

How many pennies could you have if: When you break the pennies into groups of 2, you have 1 penny left over, AND when you break

the pennies into groups of 3, you have 1 penny left over, AND when you break the pennies into groups of 5, you have 1 penny left over, AND when you break the pennies into groups of 7, you have NO pennies left over?
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

91

Step-by-step explanation:

"When you break the pennies into groups of 2, you have 1 penny left over"

You have an odd number of pennies.

"when you break the pennies into groups of 3, you have 1 penny left over"

The number of pennies is one more than a multiple of 3.

"when you break the pennies into groups of 5, you have 1 penny left over"

A number that is divisible by 5 ends in 0 or 5. You have one more penny than that, so the number will end in 1 or 6. We already know the number is odd, so it cannot end in 6. The number of pennies must end in 1.

"when you break the pennies into groups of 7, you have NO pennies left over"

The number is a multiple of 7.

We need a multiple of 7 that ends in 1.

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, ...

You could have 91.

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A young girl found an attractive stone in the woods and sold it to a jeweler for $1. Later, her family discovered that the stone
Liula [17]

Answer: The Jeweler

Step-by-step explanation:

The law states that children are to be considered legally incompetent and as such can't effectively protect their own interests. Since they are legally incompetent to protect their interests, this responsibility now falls on the individual they are dealing with.

The Jeweler is expected to protect the rights of the young girl and as where it is proven that her interests were not properly protected, such contracts can be voided based on this. The Jeweler is also expected to have significant knowledge on the values of jewelries and could properly estimate the value of the stone as at the point the transaction was made. Again the contract can be voided on the grounds of fraud in the inducement. Since he chose not to properly represent the value of the stone to an incompetent party.

4 0
4 years ago
Gin Rummy and are holding 10 cards in your hand from a standarddeck of 52 cards. Find the probability t
zepelin [54]

Here is the correct question

Gin Rummy and are holding 10 cards in your hand from a standard deck of 52 cards.

a) How many ways can you select three kings and four 6's from the deck, the remaining cards not kings or 6's

b) Find the probability that three kings and four 6's are being held by you from the deck.

Answer:

a) 52976

b) \mathbf{3.34866744 \times 10^{-6}}

Step-by-step explanation:

So from the information above,

no of ways three kings can be selected and four 6's from the deck without the remaining cards being kings or 6's can be expressed as:

no of ways to select 3 kings from 4 kings is (^4_3)

no of ways to select 4 6's from (4 6's) is (^4_4)

no of ways to select the remaining 3 cards from (52 - 4 - 4) = 44 cards is (^{44}_3)

Mathematically, multiplying the three together we have:

= (^4_3) (^4_4) (^{44}_3)

= \dfrac{4!}{3!(4-3)!}   \times \dfrac{4!}{4!(4-4)!} \times \dfrac{44!}{3!(44-3)!}

= 4  \times 1 \times 13244

= 52976

To find the probability that you are holding three kings and four 6's from the deck, the remaining cards not kings or 6's can be calculated as follows;

To do this, we need to first know the no of ways we can  select 10 cards out of the pack of 52 cards

i.e

(^{52}_{10})

= \dfrac{52!}{10!(52-10)!}

= \dfrac{52!}{10!(42)!}

= 1.58200242 × 10¹⁰

Now, to find the  probability that you are holding three kings and four 6's from the deck, the remaining cards not kings or 6's :

we will need to divide the number of ways we can select three kings and four 6's from the deck by the no of ways we can select 10 cards out of the pack of 52 cards.

Mathematically; we have,

=\dfrac{52976}{1.58200242 \times 10^{10}}

= \mathbf{3.34866744 \times 10^{-6}}

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HELP ME PLS ITS 3AM IM TIRED // geometry HL AND CPCTC
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Answer:

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Step-by-step explanation:

angle b = angle e = 90 (given) R

if ac = df H

bc = ef (given) S

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