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GREYUIT [131]
3 years ago
13

The two plots below show the heights of some sixth graders and some seventh graders of a school:/Users/tylerleaird/Desktop/Scree

n Shot 2017-04-25 at 10.53.09 AM.png.The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 0.7. Approximately how many times the variability in the heights of the seventh graders is the variability in the heights of the sixth graders? (Round all values to the tenths place.)
0.5
1.2
1.7
3.4
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
0.5 will be rounded to 1.0
1.2 will be rounded to 1.0
1.7 will be rounded to 2.0
3.4 will be rounded to 3.0
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Geometry math question no Guessing and Please show work
Alona [7]

Well, if point C is dilated by 5/3, C' should be (3*5/3, -6*5/3)

This is equivalent to Option A, (5, -10)

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What is m∠CDE?
BigorU [14]

Answer:

45°

Step-by-step explanation:

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True or False: If you roll a six-sided die ten times, you will roll an even number at least once.
Shtirlitz [24]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Randy rented a rectangular storage shed with the volume of 357 ft does it sheds height is 8 and 1/2 ft and the width of is 6 ft
ollegr [7]

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

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7 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
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