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Alina [70]
3 years ago
9

On her first shot, a golfer hit the ball 167 yards. On her second shot, she hit the ball another 49 feet and made it almost to t

he hole. On her final shot, the ball went only 7 inches before going in the hole. How many total inches did the ball travel?
Mathematics
2 answers:
guapka [62]3 years ago
8 0

the answer is 6607 if it has to be in total inches

167*36=6012 49*12=588 6012+588=6607

Morgarella [4.7K]3 years ago
6 0
If you add 167 + 49 that = 216 then you just have the add 7 to 216 which = 223.

so your answer is 223
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Step-by-step explanation:

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5 0
3 years ago
Use the magic penny parable to determine how much money you would have after 8 days.
Anit [1.1K]

Use the formula T(x) = 0.01x2^x

X is the number of days.

T(8) = 0.01 x 2^8

T(8) = 0.01 x 256

T(8) = $2.56

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3 years ago
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Step-by-step explanation:

8 0
3 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
Ill give brainliest i really need help on this
Sever21 [200]
I think the answer is

B.
8 0
2 years ago
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