Let Mary's age be x.
Paul is three times as old as Mary, so Paul's age would be 3x.
Peter is four times as old as Mary, so Peter's age would be 4x.
The sum of their ages is 64
⇒ Paul's age+ Peter's age+ Mary's age= 64
⇒ 3x+ 4x+ x= 64
⇒ 8x= 64
⇒ x= 64/8
⇒ x= 8
Paul's age is: 3x= 3*8= 24
Peter's age is: 4x= 4*8= 32
Final answer: Paul is 24 years old.
Peter is 32 years old.
Mary is 8 years old.
Hope this helps~
Sophia is 12. Four times that is 48. If her mother is 5 years less than this, she is 43.
(12 x 4) - 5 = 43
The bases were not the same when the exponents were set equal to each other.
16 should have been written as 4 squared.
The exponent on the right should be 4a instead of 8a.
The correct solution is a=-3/4.
The answer is 18. F(2) is saying that x is equal to 2. so where ever there is an x in the problem you should fill in 2 for. then all you have to do is type it into a graphing calculator and solve.
Its just simply 6.8*10^10
