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3 years ago

Can sombody please confirm me the formula for SA(surface area) of a triangular prism. please.

1 answer:

mote1985 [20]3 years ago

6 0

$bh + l(s_1 + s_2 + s_3)$
b = base length (of triangle)
h = height of triangle
s = side length of triangle
l = length of rectangle

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What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

2 years ago

Please help me find x using pythagorean theorem

astra-53 [7]

a2+b2=c2

a=x

b=24

c=26

a2+24 squared=26 squared

a2+576=676

-576 -576

a2=100

Then, square root both sides.

It should be a/x=10

3 0

3 years ago

Read 2 more answers

Please help me! And please no scam answers

Yuri [45]

Answer:

Average rate of change: $-3$

Step-by-step explanation:

Remember:

The average rate of change of a function over an interval $[a,b]$ is $\frac{f(b)-f(a)}{b-a}$

Given:

$[a,b]=[1,7]$

$f(b)=f(7)$

$f(a)=f(1)$

Calculation:

$f(b)=f(7)=-(7)^2+5(7)+14=-49+35+14=-49+49=0$

$f(a)=f(1)=-(1)^2+5(1)+14=-1+5+14=4+14=18$

$\frac{f(b)-f(a)}{b-a}=\frac{0-18}{7-1}=\frac{-18}{6}=-3$

Therefore, the average rate of change of the function $g(x)=-x^2+5x+14$ over the interval $1\leq x\leq7$ is $-3$ .

6 0

2 years ago

mike says that 3/3 of his fraction model is shaded blue and Ryan says that6/6shaded blue are the two fraction equivalent what's

Rina8888 [55]

Yes the fractions are equivalent. 5/5 is another equivalent fraction

5 0

3 years ago

Read 2 more answers

Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.

Naily [24]

The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube.

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

$V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}$

8 0

3 years ago