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Iteru [2.4K]
3 years ago
15

What is the range of the function y = x 2?

Mathematics
1 answer:
Leno4ka [110]3 years ago
5 0

Answer:

\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

Step-by-step explanation:

Given the function

y=x^2

  • We know that the range of a function is the set of values of the dependent variable for which a function is defined.

\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)

\mathrm{If}\:a

\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v

a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)

f\left(x\right)\ge \:0

Thus,

\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

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Find the volume of the sphere whose radius is 0.8 cm
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2.14 cm^3

Step-by-step explanation:

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Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

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leonid [27]

Answer: See the diagram below

==========================================================

Explanation:

She starts off finding the mean of the data. So she adds up the values to get 48+54+57+62+69 = 290, and then divides by 5 to get the mean of 290/5 = 58. That explains why there's a 58 in the first row of the second column.

---------------------

For the next step, she subtracts 58 from each data item. If the result is negative, then go with the positive version (ie apply the absolute value)

  • |48-58| = 10
  • |54-58| = 4
  • |57-58| = 1
  • |62-58| = 4
  • |69-58| = 11

This leads to the list 10,4,1,4,11 which goes in the first slot labeled "drag and drop an item here". This is the list of distance values each item is from the mean.

---------------------

The last thing to do is find the mean of the set {10,4,1,4,11}

add: 10+4+1+4+11 = 30

divide by five: 30/5 = 6

The mean absolute deviation (MAD) is 6

This represents the average distance each data value is from the mean.  The MAD tells us how spread out the data is. It's similar to the standard deviation.

6 0
2 years ago
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