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Murrr4er [49]
3 years ago
12

Which point is on the circle described by (x - 2)2 + (y + 3)2 = 4?

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
The first one (2,-5)
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First to answer correclty gets brainleist! thx :)
Fittoniya [83]

Answer:

132 square centimeter

Step-by-step explanation:

Formula of a triangle: Area= base*height/2

Formula of a rectangle: Area=base * height

Triangle: base:8cm*height:3cm=24/2=12

Since there are two triangle that matches the same area, 12+12

Side Rectangle: base:6cm*height:5cm=30

Since there are two side rectangle with the same area, add 30+30

Bottom rectangle: base:6cm*height:8cm=48

Add all of them together:

12+12+30+30+48=132 square cm

5 0
4 years ago
The two lines below intersect as shown What is the value of x?
Rufina [12.5K]

Answer:

x = 6

Step-by-step explanation:

because we know the lines intersect we also know the 2 angles are vertical meaning they are equal to each other

Knowing the angles are equal to each other you can make the equation

2x + 29 = 9x - 13

then you solve for x in this equation

2x + 29 = 9x - 13

(subtract 2x from both sides)

29 = 7x - 13

(add 13 to both sides)

42 = 7x

(divide by 7 on both sides)

6 = x

x = 6

6 0
4 years ago
1/2 divided by 3 please help me find the answer
Reil [10]

Answer:

7/15

Step-by-step explanation:

4 0
3 years ago
Write the quadratic function with the following transformations: vertical shrink by 3, left 4, down 9.
allsm [11]
Y=x^2
y=1/3(x+4)^2-9
Hope this helps
3 0
4 years ago
How many points of intersection are there between the graphs of the hyperbola and ellipse?
N76 [4]

The point of intersection is the point where two or more functions meet.

The graphs of the hyperbola and ellipse have 0 point of intersection

The given parameters are:

\mathbf{3x^2 - 4y^2 + 4x - 8y + 4 = 0}

\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 0}

To determine the points of intersection, we simply equate both equations.

So, we have:

\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 3x^2 - 4y^2 + 4x - 8y + 4 }

Cancel out the common terms

\mathbf{y^2 - 3y = - 4y^2 - 8y  }

Collect like terms

\mathbf{y^2 +4y^2= 3y   - 8y  }

\mathbf{5y^2= - 5y  }

Divide through by 5

\mathbf{y^2= - y}

Divide through by y

\mathbf{y= -1}

<em>The system of equation does not give room to calculate the x-coordinate at the x-axis.</em>

<em />

Hence, the graphs of the hyperbola and ellipse have <em>0 point of intersection</em>

Read more about points of intersection at:

brainly.com/question/13373561

4 0
3 years ago
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