Question

What is the answer to this equation 2 + 1/6y = 3x + 4

Answer 1

2 + 1/6y = 3x + 4
2 - 4 = 3x - 1/6y
-2 = 3x - 1/6y

But if you have to find x & y do this…

To solve for x. (Make y = 0)

3x - 1/6y = (-2)
3x - 1/6(0) = (-2)
3x - 0 = (-2)
3x = (-2)
x = (-2) / 3
x = -2/3 or -0.67

To solve for y. (Make x = 0)

3x - 1/6y = (-2)
3(0) - 1/6y = (-2)
0 - 1/6y = (-2)
-1/6y = (-2)
y = (-2) / -1/6
y = 12

Answer 2

Answer:

When $y=1$, $x=\frac{11}{18}$

When $x=1$, $y=\frac{1}{30}$

Step-by-step explanation:

$2 + \frac{1}{6y} = 3x + 4$

$2 -4+ \frac{1}{6y} = 3x$

$-2= 3x-\frac{1}{6y}$

The only way to find the values for this equation is find values of $x$ and $y$ relative to each other.

That means we substitute a value for $x$  and find the value of  $y$ for that particular $x$ value.

Let's find $x$ when $y=1$:

$-2= 3x-\frac{1}{6y}$

$-2= 3x-\frac{1}{6\times1}$

$-2= 3x-\frac{1}{6}$

$-2+\frac{1}{6}= 3x$

$\frac{11}{18}= x$

Therefore, when $y=1$, $x=\frac{11}{18}$

Let's find $y$ when $x=1$:

$-2= 3x-\frac{1}{6y}$

$-2= 3\times1-\frac{1}{6y}$

$-2= 3-\frac{1}{6y}$

$\frac{1}{6y}= 3+2$

$\frac{1}{6y}= 5$

$\frac{1}{6\times5}= y$

$\frac{1}{30}= y$

Therefore, when $x=1$, $y=\frac{1}{30}$