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son4ous [18]
3 years ago
14

What is the answer to this equation 2 + 1/6y = 3x + 4

Mathematics
2 answers:
Levart [38]3 years ago
5 0
2 + 1/6y = 3x + 4
2 - 4 = 3x - 1/6y
-2 = 3x - 1/6y

But if you have to find x & y do this…

To solve for x. (Make y = 0)

3x - 1/6y = (-2)
3x - 1/6(0) = (-2)
3x - 0 = (-2)
3x = (-2)
x = (-2) / 3
x = -2/3 or -0.67

To solve for y. (Make x = 0)

3x - 1/6y = (-2)
3(0) - 1/6y = (-2)
0 - 1/6y = (-2)
-1/6y = (-2)
y = (-2) / -1/6
y = 12
IrinaVladis [17]3 years ago
4 0

Answer:

When y=1, x=\frac{11}{18}

When x=1, y=\frac{1}{30}

Step-by-step explanation:

2 +  \frac{1}{6y} = 3x + 4

2 -4+  \frac{1}{6y} = 3x

-2= 3x-\frac{1}{6y}

The only way to find the values for this equation is find values of x and y relative to each other.

That means we substitute a value for x  and find the value of  y for that particular x value.

Let's find x when y=1:

-2= 3x-\frac{1}{6y}

-2= 3x-\frac{1}{6\times1}

-2= 3x-\frac{1}{6}

-2+\frac{1}{6}= 3x

\frac{11}{18}= x

Therefore, when y=1, x=\frac{11}{18}

Let's find y when x=1:

-2= 3x-\frac{1}{6y}

-2= 3\times1-\frac{1}{6y}

-2= 3-\frac{1}{6y}

\frac{1}{6y}= 3+2

\frac{1}{6y}= 5

\frac{1}{6\times5}= y

\frac{1}{30}= y

Therefore, when x=1, y=\frac{1}{30}

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